我想在 ASP 中创建一个日志功能,为此我需要能够解析 UPDATE sql 语句。 如果我有这样的 SQL 语句:
UPDATE mytable SET aaa='test',bbb=123 WHERE id=508
我想得到的输出是像这样表示字段和值的数组:
FieldArray = aaa,bbb
ValueArray = test,123
我如何在 ASP 中或直接在 SQL 中执行此操作?
最佳答案
忘记使用 SQL。它的作用是使用、访问和修改数据库服务器上的数据。
在 VB.NET 中,您可以使用 Left
、Mid
、Right
和 InStr
函数来解析输出你的 SQL 字符串。
' Using your string : UPDATE mytable SET aaa='test',bbb=123 WHERE id=508
strWithoutFirstPart = Mid(strSQL, InStr(strSQL, "SET")) ' Output : SET aaa='test',bbb=123 WHERE id=508
strWithoutLastPart = Left(strWithoutFirstPart, InStr(strWithoutFirstPart, "WHERE")-1) ' OutPut : SET aaa='test',bbb=123
This has more information on the functions .
这是我为您的问题制定的程序:
'Global variables
Dim parameters, values
parameters = Array()
values = Array()
' Procedure for parsing an Update SQL Statement to get parameters and values.
Sub parseSQLUpdate(ByVal strSQL)
' Variables
Dim strParsed, intEqualPos, intCommaPos, intLastPos, regExStrCommaTest
' Clearing the global variables.
ReDim parameters(0), values(0)
' Parsing the string for the right section.
strParsed = Trim(Mid(strSQL, InStr(UCase(strSQL), "SET") + 4))
strParsed = Trim(Left(strParsed, InStr(UCase(strParsed), "WHERE") - 2))
' Getting positions.
intEqualPos = InStr(strParsed, "=")
intCommaPos = InStr(strParsed, ",")
intLastPos = 0
' Preparing the Reg. Ex. variable
Set regExStrCommaTest = new RegExp
regExStrCommaTest.Pattern = "('[^']*'$)|(^[^']+$)"
' Looping for every parameter/value.
Do While (intEqualPos > 0)
' Check if first loop.
If (intLastPos = 0) Then
parameters(UBound(parameters)) = Trim(Left(strParsed, intEqualPos - 1))
' Check if at last parameter/value.
If (intCommaPos > 0) Then
' Check for commas in text.
Do While (regExStrCommaTest.Test(Trim(Mid(strParsed, intEqualPos + 1, intCommaPos - intEqualPos - 1))) = False)
' Go to next comma.
intCommaPos = InStr(intCommaPos + 1, strParsed, ",")
' Already at end, so take remaining characters.
If (intCommaPos <= 0) Then
values(UBound(values)) = Trim(Mid(strParsed, intEqualPos + 1))
Exit Sub
End If
Loop
values(UBound(values)) = Trim(Mid(strParsed, intEqualPos + 1, intCommaPos - intEqualPos - 1))
Else
values(UBound(values)) = Trim(Mid(strParsed, intEqualPos + 1))
End If
Else
' Change arrays' size.
ReDim Preserve parameters(UBound(parameters) + 1), values(UBound(values) + 1)
parameters(UBound(parameters)) = Trim(Mid(strParsed, intLastPos + 1, intEqualPos - intLastPos - 1))
' Check if at last parameter/value.
If (intCommaPos > 0) Then
' Check for commas in text.
Do While (regExStrCommaTest.Test(Trim(Mid(strParsed, intEqualPos + 1, intCommaPos - intEqualPos - 1))) = False)
' Go to next comma.
intCommaPos = InStr(intCommaPos + 1, strParsed, ",")
' Already at end, so take remaining characters.
If (intCommaPos <= 0) Then
values(UBound(values)) = Trim(Mid(strParsed, intEqualPos + 1))
Exit Sub
End If
Loop
values(UBound(values)) = Trim(Mid(strParsed, intEqualPos + 1, intCommaPos - intEqualPos - 1))
Else
values(UBound(values)) = Trim(Mid(strParsed, intEqualPos + 1))
End If
End If
' Remembering last position
intLastPos = intCommaPos
' Ending Loop if last position is 0
If (intLastPos = 0) Then
Exit Sub
End If
' Getting new positions.
intEqualPos = InStr(intLastPos, strParsed, "=")
intCommaPos = InStr(intEqualPos, strParsed, ",")
Loop
End Sub
关于asp.net - 解码/解析 UPDATE sql 语句,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/6983656/