MySQL - 每个值都在

Question

以下查询选择输入“完成”的所有工作单元(第 7 行的子查询)。这很好用……当只有一个输入时。我该如何更改它，以便它要求每个 输入都在子查询返回的集合中，而不仅仅是要出现的输入之一？

SELECT workunits.ID 
FROM workunits 
LEFT JOIN workunitInputs ON workunits.ID = workunitInputs.workunitID 
WHERE workunits.ID NOT IN (SELECT workunitID FROM jobworkunitassoc) 
AND ( 
    workunitInputs.inputID IN ( 
        SELECT workunitOutputs.outputID 
        FROM workunitOutputs 
        LEFT JOIN workunits ON workunitOutputs.workunitID = workunits.ID 
        LEFT JOIN jobworkunitassoc ON workunits.ID = jobworkunitassoc.workunitID 
        LEFT JOIN jobs ON jobworkunitassoc.jobID = jobs.ID 
        WHERE jobs.done = 1 
    ) 
    OR workunitInputs.inputID IS NULL 
) 
GROUP BY workunits.ID

谢谢，伊斯特万。

Answer 1

将该条款更改为:

AND ( 
    workunitInputs.inputID NOT IN ( 
        SELECT workunitOutputs.outputID 
        FROM workunitOutputs 
        LEFT JOIN workunits ON workunitOutputs.workunitID = workunits.ID 
        LEFT JOIN jobworkunitassoc ON workunits.ID = jobworkunitassoc.workunitID 
        LEFT JOIN jobs ON jobworkunitassoc.jobID = jobs.ID 
        WHERE jobs.done != 1 
    )

这是基于逻辑重言式:All X in Y === No X in !Y