我有这个问题:
SELECT bi.id,
bi.location,
bi.expense_group,
bi.level,
bi.is_active,
bi.type,
full_name,
( bl.bud_amount ) AS BudgetAmount,
( COALESCE(( ( bl.bud_amount * 3 ) - (
+ bal.bal_amount1 + bal.bal_amount2
+ bal.bal_amount3 ) ), 0) ) AS Difference,
( COALESCE(Round(( + bal.bal_amount1 + bal.bal_amount2
+ bal.bal_amount3 ) / 3), 0) ) AS Average,
bal.bal_amount1 AS BAL1,
bal.bal_amount2 AS BAL2,
bal.bal_amount3 AS BAL3
FROM (SELECT *
FROM budget_items bi
WHERE bi.location IS NOT NULL) AS bi
LEFT JOIN (SELECT budget_item_id,
Sum(CASE
WHEN budget_id = 21491 THEN amount
END) AS bud_amount
FROM budget_lines
GROUP BY budget_item_id) AS bl
ON bl.budget_item_id = bi.id
JOIN (SELECT budget_item_id,
Ifnull(Sum(CASE
WHEN balance_id = 12841 THEN amount
END), 0) AS bal_amount1,
Ifnull(Sum(CASE
WHEN balance_id = 18647 THEN amount
END), 0) AS bal_amount2,
Ifnull(Sum(CASE
WHEN balance_id = 18674 THEN amount
END), 0) AS bal_amount3
FROM balance_lines
GROUP BY budget_item_id) AS bal
ON bal.budget_item_id = bi.id
ORDER BY bi.location
这需要很多时间。在 budget_lines 和 balance_lines 表中,每个表都有超过 5,000,000 行。
我还附上了查询的 EXPLAIN,因此您将无法看到问题所在。 每个表中的所有 ID 都已编入索引。是否有任何列可以被索引以加快查询速度?或者我可能需要更改它。
*** LEFT JOIN 是必要的,因为我需要从 nudget_items 中获取所有项目,即使它们不存在于 balance/budget_line 表中。
架构是:每个预算都有它的 budget_lines。每个余额都有其 balance_lines。该查询的目的是用一个表来汇总预算和多个余额之间的差异。
您可以在这里看到更大的图像:http://i.stack.imgur.com/dlF8V.png
编辑: @Sebas 回答后:
对于@sabes 的饥饿,我把描述放在这里: 预算项目
budget_lines
平衡线
最佳答案
也许是这样的;但是没有样本数据和索引很难看
SELECT *
FROM budget_items bi
WHERE bi.location IS NOT NULL) AS bi
INNER JOIN --Added inner for clarity -changed order I just like my inner's before my outers.
(SELECT budget_item_id, Sum(CASE WHEN balance_id = 12841 THEN coalesce(amount,0) END), 0) AS bal_amount1,
Sum(CASE WHEN balance_id = 18647 THEN coalesce(amount,0) END), 0) AS bal_amount2,
Sum(CASE WHEN balance_id = 18674 THEN coalesce(amount,0) END), 0) AS bal_amount3
FROM balance_lines
WHERE balance_ID in (12841, 18647, 18674) --This way balance_IDs which aren't in this list don't even get evaluated
GROUP BY budget_item_id) AS bal
ON bal.budget_item_id = bi.id
LEFT JOIN
(SELECT budget_item_id, Sum(CASE WHEN budget_id = 21491 THEN coalesce(amount,0) END) AS bud_amount
FROM budget_lines
WHERE budget_Id = 21491 --Again since we only care about anything but budget_ID 21491, we can limit the results to JUST that
GROUP BY budget_item_id) AS bl
ON bl.budget_item_id = bi.id
关于Mysql - 帮助优化查询,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/15385335/