我正在尝试合并按 threadid 分组并按 last_activity 排序的消息和聊天表。当我尝试使用 UNION 时,我在排序时遇到了问题,所以我假设 join 会做得更好。我在语法方面遇到问题,希望得到一些指导。以下是我正在使用的两个选择。非常感谢任何帮助。
从消息表中选择:
mysql> select threadid, uidto, uidfrom, last_activity, last_message from messages group by threadid order by last_activity DESC;
+----------+-------+---------+---------------------+------------------+
| threadid | uidto | uidfrom | last_activity | last_message |
+----------+-------+---------+---------------------+------------------+
| 2 | 2 | 1 | 2013-09-06 22:59:38 | blurred lines... |
| 1 | 9 | 1 | 2013-09-06 22:49:16 | kisses! |
+----------+-------+---------+---------------------+------------------+
2 rows in set (0.00 sec)
从聊天表中选择:
mysql> select threadid, uidto, uidfrom, last_activity, last_message from chat group by threadid order by last_activity DESC;
+----------+-------+---------+---------------------+--------------+
| threadid | uidto | uidfrom | last_activity | last_message |
+----------+-------+---------+---------------------+--------------+
| 2 | 2 | 1 | 2013-09-06 23:03:27 | danke |
| 1 | 1 | 9 | 2013-09-06 22:30:34 | much |
+----------+-------+---------+---------------------+--------------+
2 rows in set (0.00 sec)
最佳答案
select m.threadid, m.uidto, m.uidfrom, m.last_activity, m.last_message,
c.threadid, c.uidto, c.uidfrom, c.last_activity, c.last_message
FROM messages m
JOIN chat c on m.threadid=c.threadid
GROUP by threadid ORDER BY last_message
(select m.threadid, m.uidto, m.uidfrom, m.last_activity, m.last_message FROM messages m
UNION ALL
select c.threadid, c.uidto, c.uidfrom, c.last_activity, c.last_message FROM chat c)
GROUP by threadid ORDER BY last_message
关于php - 使用 GROUP BY 和 ORDER BY 条件在两个 MySQL 表上加入与联合,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/18668179/