请帮助我,我正在聊天,但只有发送消息的用户可以看到它。另一个不能,例如:
以 David 身份登录:
(无法上传照片)
-我:你好
-ME:啦啦啦啦
以Shinny身份登录:
-ME:嘻嘻嘻
本以为shinny写的内容应该显示在我的聊天中,我写的内容应该显示在shinny的聊天中,但是传入的消息没有显示
应该怎样
-我:你好
-Shinny:嘻嘻嘻
-ME:啦啦啦啦
这是代码:我能做些什么来解决这个问题?
<?php
$chaquery = "SELECT u.*,c.* FROM chats c
INNER JOIN users u WHERE u.user_id = c.chat_from
AND chat_from = '".$session['user_id']."'
AND chat_to = '".$_GET['id']."'
(最终用户的id)
OR u.user_id = c.chat_to AND u.user_id = c.chat_from
AND chat_to = '".$session['user_id']."'
AND chat_from = '".$_GET['id']."'
(再次是命运用户的 id)
ORDER BY chat_id ";
$chares = mysql_query($chaquery);
if($chares)
{
while($chafilas = mysql_fetch_assoc($chares))
{
$me = $chafilas["chat_remit"];
$message = $chafilas["chat_cont"];
$hour = $chafilas["chat_hora"];
$date = $chafilas["chat_fecha"];
$day = $chafilas["chat_dia"];
$fullname = $chafilas["usuario_nombre"];
$nick = $chafilas["usuario_nick"];
$userphoto = $chafilas["usuario_foto"];
if($me){?><div class="panel-body">
<img src="avatar/<?php echo $tufoto;?>" style="float:left; margin-right:10px;" width="55px" class="ui"/>
<a href="<?php echo $xnick;?>"><b style="font-size:16px;"><?php echo $xnombre;?></b></a><br><?php echo $xmensaje;?>
</div><?php }}}?>
这里是表格
`chat_id` int(11) NOT NULL AUTO_INCREMENT,
`chat_from` varchar(45) COLLATE utf8_bin NOT NULL,
`chat_to` varchar(45) COLLATE utf8_bin NOT NULL,
`chat_message` longtext COLLATE utf8_bin NOT NULL,
`chat_hour` varchar(10) COLLATE utf8_bin NOT NULL,
`chat_day` varchar(2) COLLATE utf8_bin NOT NULL,
`chat_date` varchar(7) COLLATE utf8_bin NOT NULL,
`chat_seen` varchar(2) COLLATE utf8_bin NOT NULL,
PRIMARY KEY (`chat_id`)
最佳答案
您的代码没有任何问题..您是否将这些聊天内容保存在某个地方??如果是的话,你必须使用像这样的 ajax 调用来刷新包含你的聊天消息的特定 div....
<script type="text/javascript">
$(function() {
//populating chat the first time
refresh_chat();
// recurring refresh every 1 seconds
setInterval("refresh_chat()", 1000);
$("#send").click(function() {
// getting the values that user typed
var send = $("#send").val();
var chat = $("#chat").val();
var data = 'add='+ add + '&comp='+ comp;
$.ajax({
type: "POST",
url: "chat.php",
data: data,
success: function(html){
// this happen after we get result
$("#scroll").fadeOut(500, function(){
$(this).html(html).fadeIn(500);
$("#scroll").val("");
//alert('hello');
});
});
return false;
}
function refresh_shoutbox() {
var data = 'refresh=1';
$.ajax({
type: "POST",
url: "chat.php",
data: data,
success: function(html){ // this happen after we get result
$("#chat").html(html);
}
});
});
});
</script>
希望这对你有帮助:)
关于php - 传递消息时出错 我自己的 PHP Chat,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/20026869/