mysql - Zend Framework 2 无法从联接表中获取字段

Question

我无法从联接表中获取字段。这是我的情况，我有两个名为“query”和“region”的表，由两个 Controller QueryCOntroller 和 RegionController 处理。我尝试从 QueryController 将“查询”加入“区域”。在 View 文件中获取“查询”的“区域”名称的名称，但我无法获取所需的字段

public function fetchMine($myid)
{
    $sql = new Sql( $this->tableGateway->adapter ) ;
    $where = new Where() ;

    $where->equalTo('agent_id', $myid) ;

    $select = $sql->select() ;
    $select -> from ( $this->tableGateway->getTable() )
    -> join ( 'region' , 'query.agent_id = region.id')
    ->columns(array('*'))
    -> where( $where ) ;

    $resultSet = $this->tableGateway->selectWith($select);
    return $resultSet;
}

在我的 Module.php 中，getServiceConfig()

'Management\Model\QueryTable' =>  function($sm) {
    $tableGateway = $sm->get('QueryTableGateway');
    $table = new QueryTable($tableGateway);
    return $table;
},
'QueryTableGateway' => function ($sm) {
    $dbAdapter = $sm->get('Zend\Db\Adapter\Adapter');
    $resultSetPrototype = new ResultSet();
    $resultSetPrototype->setArrayObjectPrototype(new Query());
    return new TableGateway('query', $dbAdapter, null, $resultSetPrototype);
},

Answer 1

尝试:

public function fetchMine($myid)
{       
    $select = new Select ();
    $select->from ( $this->tableGateway->getTable() );
    $select->join ( 'region' , 'query.agent_id = region.id' , Select::SQL_STAR , Select::JOIN_LEFT )
    $select->where( array( 'agent_id'=>$myid ) );

    $resultSet = $this->tableGateway->selectWith($select);
    return $resultSet;
}

那么你必须从 Region 扩展 Query 以获得查询和区域的所有属性， 查询.php:

use Management\Model\Region;
class Query extends Region
{
    //...
}