php - SQL ORDER String (NumberOrder/CurrentYear) 来自两个表

Question

我有表一和表二，两者都有一个名为“n_inscription”的字段

我将此值作为“n_inscription”LIKE This (NumberOrder/CurrentYear) VARCHAR 保存到 MySQL 数据库中 保存在两个表中。示例:1/2013、2/2013、13/2014、....等(表一) 和表二有这些值

1/2014, 2/2014,  5/2013...

我试过这个查询:

$list_students = array();

$sql_students = $mysqli->query("SELECT * FROM `es_student_infos`
                                        WHERE school_year='".$school_year."'                                                                    
                                        ORDER BY
                                        CAST(RIGHT(n_inscription, 4) AS UNSIGNED) ASC,
                                        CAST(LEFT(n_inscription, LOCATE('/', n_inscription) - 1) AS UNSIGNED) ASC");

        while($data1 = $sql_students->fetch_object()){
            $list_students[] = $data1;
        }

        $sql_students2 = $mysqli->query("SELECT * FROM `es_upgrades`
                                        WHERE school_year='".$school_year."'                                                                    
                                        ORDER BY
                                        CAST(RIGHT(n_inscription, 4) AS UNSIGNED) ASC,
                                        CAST(LEFT(n_inscription, LOCATE('/', n_inscription) - 1) AS UNSIGNED) ASC");

        while($data2 = $sql_students2->fetch_object()){
            $list_students[] = $data2;
        }

//检索数据:

foreach($list_students AS $student): 
............
endforeach;

此查询中的问题是它对第一个表中的数据进行排序，然后对第二个表中的数据进行排序，结果如下:

1/2013| 2/2013 | 13/2014 | 5/2013 | 1/2014 | 2/2014 | 

查询似乎开始对表一中的数据进行排序，当它完成数据排序后，它再次开始对表二中的数据进行排序。

我想同时对两个表中的数据进行排序，得到这样的结果:

1/2013| 2/2013 | 5/2013 | 1/2014 | 2/2014 | 13/2014 |

而不是

1/2013| 2/2013 | 13/2014 | 5/2013 | 1/2014 | 2/2014 |

表格结构:

表一:

 `es_student_infos` (
  `id_student` int(11) NOT NULL,
  `id_grade` int(11) NOT NULL,
  `id_class` int(11) NOT NULL,
  `n_inscription` varchar(255) NOT NULL,
  `date_inscription` date NOT NULL,
  `cne` varchar(255) NOT NULL,
  `nom_fr` varchar(255) NOT NULL,
  `nom_ar` varchar(255) CHARACTER SET utf8 NOT NULL,
  `prenom_fr` varchar(255) NOT NULL,
  `prenom_ar` varchar(255) CHARACTER SET utf8 NOT NULL,
  `date_naissance` date NOT NULL,
  `lieu_naissance_ar` varchar(255) CHARACTER SET utf8 NOT NULL,
  `lieu_naissance_fr` varchar(255) NOT NULL,
  `tel` varchar(255) NOT NULL,
  `sexe` varchar(10) CHARACTER SET utf8 NOT NULL,
  `ancien_niveau_scolaire` varchar(255) CHARACTER SET utf8 NOT NULL,
  `date_ancienNiveauScolaire` varchar(10) NOT NULL,
  `ancienne_ecole` varchar(255) CHARACTER SET utf8 NOT NULL,
  `type_ecole` varchar(255) CHARACTER SET utf8 NOT NULL,
  `type_inscription` varchar(20) CHARACTER SET utf8 NOT NULL,
  `assurance` int(11) NOT NULL,
  `mensualite` int(11) NOT NULL,
  `nom_tuteur` varchar(255) CHARACTER SET utf8 NOT NULL,
  `profession_tuteur` varchar(255) CHARACTER SET utf8 NOT NULL,
  `adresse_tuteur` varchar(255) CHARACTER SET utf8 NOT NULL,
  `tel_tuteur` varchar(255) NOT NULL,
  `remarques` text CHARACTER SET utf8 NOT NULL,
  `photo` varchar(255) NOT NULL,
  `school_year` varchar(10) NOT NULL,
  `cours_type` enum('jour','soir') NOT NULL,
  `id_subject` int(11) NOT NULL,
  `id_prof_soir` varchar(30) NOT NULL,
  `montant_soir` varchar(255) NOT NULL,
  `archived` enum('0','1') NOT NULL

表二:

  `es_upgrades` (
      `id_upgrade` int(11) NOT NULL,
        `id_student` int(11) NOT NULL,
         `n_inscription` varchar(20) NOT NULL,
         `old_id_class` int(11) NOT NULL,
         `new_id_class` int(11) NOT NULL,
         `status` enum('up','down') NOT NULL,
         `school_year` varchar(30) NOT NULL,
         `date_inscription` date DEFAULT NULL,
         `cne` varchar(255) DEFAULT NULL,
         `nom_fr` varchar(255) DEFAULT NULL,
         `nom_ar` varchar(255) CHARACTER SET utf8 DEFAULT NULL,
         `prenom_fr` varchar(255) DEFAULT NULL,
         `prenom_ar` varchar(255) CHARACTER SET utf8 DEFAULT NULL,
         `date_naissance` date DEFAULT NULL,
         `lieu_naissance_ar` varchar(255) CHARACTER SET utf8 DEFAULT NULL,
         `lieu_naissance_fr` varchar(255) DEFAULT NULL,
         `tel` varchar(255) DEFAULT NULL,
         `sexe` varchar(10) CHARACTER SET utf8 DEFAULT NULL,
         `ancien_niveau_scolaire` varchar(255) CHARACTER SET utf8 DEFAULT NULL,
         `date_ancienNiveauScolaire` varchar(10) CHARACTER SET utf8 DEFAULT NULL,
         `ancienne_ecole` varchar(255) CHARACTER SET utf8 DEFAULT NULL,
         `type_ecole` varchar(255) CHARACTER SET utf8 DEFAULT NULL,
         `type_inscription` varchar(20) CHARACTER SET utf8 DEFAULT NULL,
         `assurance` int(11) DEFAULT NULL,
         `mensualite` int(11) DEFAULT NULL,
         `nom_tuteur` varchar(255) CHARACTER SET utf8 DEFAULT NULL,
         `profession_tuteur` varchar(255) CHARACTER SET utf8 DEFAULT NULL,
         `adresse_tuteur` varchar(255) CHARACTER SET utf8 DEFAULT NULL,
         `tel_tuteur` varchar(255) CHARACTER SET utf8 DEFAULT NULL,
         `remarques` text CHARACTER SET utf8,
         `photo` varchar(255) CHARACTER SET utf8 DEFAULT NULL,
         `cours_type` enum('jour','soir') CHARACTER SET utf8 DEFAULT NULL,
         `id_subject` int(11) DEFAULT NULL,
         `archived` enum('0','1') DEFAULT NULL

Answer 1

UNION 应该有效，但它仅适用于具有相同列数的表，或者如果您指定了所需的列(换句话说，您不能使用 * 符号)

所以，如果你有类似表格的表格:

CREATE TABLE a
(
 id SERIAL,
 dat DATE,

 PRIMARY KEY (id)
);

和

CREATE TABLE b
(
 id SERIAL,
 dat DATE,
 ip VARCHAR(16),

 PRIMARY KEY (id)
);

你应该使用这样的请求

SELECT dat FROM a
UNION 
SELECT dat FROM b;

那么它应该可以工作了。

并阅读此主题(尤其是第二个答案(有 7 票))可能会有所帮助:Order by descending date - month, day and year