mysql - SQL : I search the good query with select max() and select count()

Question

我有一个名为arrived的表(这个表很简单，它只保存了在某天某时到达学校的用户)，其中包含以下数据:

id  name    day         hour
1   Alice   Monday      11
2   Alice   Monday      13
3   Alice   Tuesday     11
4   Céline  Wednesday   14
5   Céline  Wednesday   13
6   Céline  Thursday    14
7   Maud    Friday      15
8   Maud    Saturday    15
9   Maud    Saturday    16

现在，我搜索为每个用户找到的好查询:最频繁的一天和最频繁的小时，也就是说，查询的结果必须返回以下行:

Alice   Monday      11
Céline  Wednesday   14
Maud    Saturday    15

=> 因为:

• Alice 经常在星期一到达，而且经常在 11 点到达
• Céline 经常在星期三到达，而且经常在 14 点到达
• Maud 经常在周六到达，而且经常在 15 点到达

我的查询如下，但没有给我好的结果:

SELECT NAME,
       day,
       Max(count_hour)
FROM   (SELECT NAME,
               day,
               Count(hour) AS count_hour
        FROM   arrived
        GROUP  BY NAME,
                  day) AS alias_table
GROUP  BY NAME 

谢谢你，诚挚的。

Answer 1

不确定这样做是否正确，但应该可行!

SELECT *
FROM   arrived A
WHERE  hour = (SELECT hour
               FROM   arrived B
               WHERE  a.NAME = b.NAME
               GROUP  BY b.hour,
                         b.NAME
               ORDER  BY Count(b.hour) DESC Limit 1)
       AND day = (SELECT day
                  FROM   arrived B
                  WHERE  a.NAME = b.NAME
                  GROUP  BY b.day,
                            b.NAME
                  ORDER  BY Count(b.day) DESC Limit 1) 

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