php - SQL 内部查询不提供输出

Question

/* 在 $selected m 中从成功存储在 $selected 中的 java 代码中获取数据。在查询中使用 $selected 但在触发查询后无法获取任何数据。 */

     $selected = $_GET['selected'];

     $projects=mysql_query("select ProjectName from projects where LobID =
                ( select LobID from lob where LobName like     ".$selected.");");

 if (!$projects) {
     echo "Could not successfully run query ($projects) from DB: " .mysql_error();
    exit;
}

  /* Have included this query in my php page. All the table names are same.Lob       and projects are two different tables n LobID is primary key in Lob & Foreign key in projects. By executing the above query I am not able to fetch the data in $projects.Instead i am getting mesagecould not successfully run query. please help. */

Answer 1

查询应该是这样的

$projects=mysql_query("select ProjectName from projects where LobID =
                     (select LobID from lob where LobName like '$selected')");

将 ".$selected."); 更改为 '$selected'