java - org.hibernate.hql.internal.ast.QuerySyntaxException : unexpected token: >= near line 1

Question

当我使用 Hibernate 运行此查询时，出现异常:

String query = "FROM A st, B g "
                + "WHERE st.name = g.name AND st.name LIKE :name AND "
                + "g.id = ANY (SELECT c FROM C "
                + "WHERE CASE WHEN name = 'test' THEN condiction >= :value end)";

        try {
            return (List) entityManager.createQuery(query)
                    .setParameter("name", "%" + name + "%")
                    .setParameter("value", value).getResultList();
        } catch (SecurityException | IllegalStateException | RollbackException e) {
            LOGGER.info(e.getMessage());
        }
        return null;

我得到了一个异常(exception):

java.lang.IllegalArgumentException: org.hibernate.hql.internal.ast.QuerySyntaxException: unexpected token: >= near line 1, column 336 ...
    at org.hibernate.jpa.spi.AbstractEntityManagerImpl.convert(AbstractEntityManagerImpl.java:1750)
    at org.hibernate.jpa.spi.AbstractEntityManagerImpl.convert(AbstractEntityManagerImpl.java:1677)
    at org.hibernate.jpa.spi.AbstractEntityManagerImpl.convert(AbstractEntityManagerImpl.java:1683)
    at org.hibernate.jpa.spi.AbstractEntityManagerImpl.createQuery(AbstractEntityManagerImpl.java:331)
    at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
    at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:62)

有什么想法吗？我使用mysql数据库。我可以在 hibernate 状态下使用 CASE WHEN THEN 吗？同样的查询在命令行上运行良好。

谢谢 干杯

Answer 1

CASE 表达式的语法不正确。应该是这样的(我觉得):

  WHERE CASE :name
    WHEN 'test' THEN condiction >= :value
    ELSE false
  END

... 除了 condiction 在这里没有任何意义。

无论如何，CASE 表达式的语法在 Java EE 6 教程中给出:

• > Full Query Language Syntax