我正在尝试基于具有多个条件和 LEN 的 IF 语句创建连接,但无法使其正常工作。
SELECT
"Datafeed-WO"."Billing Cd" AS 'Billing Type',
IF(LEN("Datafeed-WO"."Zip") = 6, 'CDA', 'USA') AS 'Country',
"BudgetTbl"."BudYr" AS 'Budget Yr',
"BudgetTbl"."Budget" AS 'Group Budget'
FROM "Datafeed-WO"
LEFT JOIN "BudgetTbl"
ON ( IF(LEN("Datafeed-WO"."Zip") = 6, 'CDA', 'USA') = "BudgetTbl"."Country")
AND ("Datafeed-WO"."Billing Cd" = "BudgetTbl"."Billing Cd")
感谢您帮助解决这个问题!
最佳答案
您需要将所有这些引号(' 和 ")更改为反引号(`)并尝试再次执行它。 从今以后,不要在表名和列名中包含空格也很重要。
希望这是你想要的:
select
dw.`Billing Cd` as `Billing_Type`,
if(len(dw.`Zip`) = 6, 'CDA', 'USA') as `Country`,
bt.`BudYr` as `Budget_Yr`,
bt.`Budget` as `Group_Budget`
from `Datafeed-WO` dw
left join `BudgetTbl` bt on (dw.`Billing Cd` = bt.`Billing Cd`) and ((len(dw.`Zip`) = 6 && bt.`Country` = 'CDA') || (len(dw.`Zip`) != 6 && bt.`Country` = 'USA'));
关于mysql - 如何在 LEFT JOIN 中使用 IF(LEN,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/33104087/