我有这样的表:
date|status|value
日期是日期, 状态为 1 为待处理,2 为已确认 值(value)是订单的值(value)
我想得到 3 列:
date|#status pending|#status pending+confirmed
数据示例:
+------------+-----------------+-----------------+
| date | status | value |
+------------+-----------------+-----------------+
| 2015-11-17 | 1 | 89|
| 2015-11-16 | 1 | 6 |
| 2015-11-16 | 2 | 16 |
| 2015-11-16 | 2 | 26 |
| 2015-11-15 | 2 | 26 |
| 2015-11-14 | 2 | 24 |
+------------+-----------------+-----------------+
我想要的例子:
+------------+-----------------+-----------------+
| date | confirmed |confirmed+pending|
+------------+-----------------+-----------------+
| 2015-11-17 | 0 | 1 |
| 2015-11-16 | 2 | 3 |
| 2015-11-15 | 1 | 1 |
| 2015-11-14 | 1 | 1 |
+------------+-----------------+-----------------+
我正在尝试:
SELECT array1.DATE
,array1.confirmed
,array2.total
FROM (
SELECT DATE (DATE) AS DATE
,count(value) AS confirmed
FROM Orders
WHERE STATUS = '2'
GROUP BY DATE (DATE) DESC limit 5
) AS array1
INNER JOIN (
SELECT DATE (DATE) AS DATE
,count(value) AS total
FROM Orders
GROUP BY DATE (DATE) DESC limit 5
) AS array2
但我每个日期得到 4 个结果,重复确认值(value)和不同的总交易。
如果我尝试分开,我可以获得两个正确的信息:
将仅列出最近 5 天已确认订单的总和:
SELECT array1.DATE
,array1.confirmed
,array2.total
FROM (
SELECT DATE (DATE) AS DATE
,count(valor) AS confirmed
FROM Orders
WHERE STATUS = '2'
GROUP BY DATE (DATE) DESC limit 5;
)
将列出最近 5 天所有订单的总和:
SELECT DATE (DATE) AS DATE
,count(valor) AS total
FROM Orders
GROUP BY DATE (DATE) DESC limit 5
我观察到至少一个大问题:
有时我们会有一天有很多未确认订单和零确认订单,因此内部连接可能会失败。
最佳答案
您可以使用CASE WHEN
,为了获得您已给出的预期输出。
SELECT `date`,
(SUM(CASE WHEN `status`=1 THEN 1 ELSE 0 END)) AS Confirmed,
(SUM(CASE WHEN `status`=1 OR `status`=2 THEN 1 ELSE 0 END)) AS Confirmed_Pending
FROM
table_name
GROUP BY DATE(`date`) DESC
希望这对您有所帮助。
关于mysql - 如何合并两个具有不同 WHERE 和特殊条件的选择,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/33764297/