php - 如果 nodeid 不是来自具有相同内容 id 的 nodeid 的标题副本，则 nodeid 是最新的

Question

我写了一个 php 文件来显示我数据库中的最后一篇文章。 我找到最后一篇文章，但最后一篇文章没有标题 我想显示最后一篇文章和其他没有标题的文章 复制自有标题且内容相同的文章。我的数据库很大。我准备了一张图片作为我的数据库的示例

the example pic

这是我的 php 代码:

<?php
$servername = "localhost";
$username = "root";
$password = "";
$dbname = "vbtest";

// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
    die("Connection failed: " . $conn->connect_error);
} 

$sql = "SELECT title , nodeid FROM node where contenttypeid='30' order by nodeid desc limit 10";
$result = $conn->query($sql);

if ($result->num_rows > 0) {
    // output data of each row
    while($row = $result->fetch_assoc()) {
        echo "title: " . $row["nodeid"]. " title: " . $row["title"]. "<br>";
    }
} else {
    echo "0 results";
}
$conn->close();
?>

谁能帮帮我？

Answer 1

那么，如何只留下一个唯一的标题和第一个 nodeid 进行排序。

SELECT * FROM
(SELECT T.title,
       MIN(nodeid) AS nodeid
FROM
    (SELECT
           (SELECT N2.title FROM node AS N2
            WHERE N2.contentid = N.contentid
                  AND N2.starter = N.starter
            ORDER BY N2.nodeid ASC
            LIMIT 1) AS title,
            nodeid
    FROM node AS N
    WHERE contentid='30' 
    ORDER BY nodeid DESC LIMIT 10) AS T
GROUP BY title 
) AS T2
ORDER BY nodeid DESC