c# - 不使用数据源控件的 gridview Inner Join 查询

Question

我正在尝试从 MySQL Workbench 中显示下表以显示在 asp.net 上

为了在 asp.net 上显示表格，我使用的是 GridView ，代码如下:

<asp:GridView ID="GridView1" runat="server" AutoGenerateColumns="False" OnRowCommand="GridView1_RowCommand" DataKeyNames ="child_id" OnSelectedIndexChanged="GridView1_SelectedIndexChanged" AllowPaging="True" OnPageIndexChanging="GridView1_PageIndexChanging">
        <Columns>
            <asp:TemplateField>
                <ItemTemplate>
                    <asp:LinkButton ID="LinkButton1" runat="server" CommandName="SelectFullDetails">Select</asp:LinkButton>
                </ItemTemplate>
            </asp:TemplateField>
            <asp:BoundField DataField="child_id" HeaderText="Id" />
            <asp:BoundField DataField="child_firstname" HeaderText="FirstName" />
            <asp:BoundField DataField="parent_surname" HeaderText="Surname" />
            <asp:BoundField DataField="club_name" HeaderText="Club" />
        </Columns>
    </asp:GridView>



        protected void Page_Load(object sender, EventArgs e)
    {
        if (!IsPostBack)
        {
            GridViewDataBind();
        }
    }

    private void GridViewDataBind()
    {
        GridView1.DataSource = DetailsAccessLayer.GetAllChildBasicDetails();
        GridView1.DataBind();
    }
 public class ChildBasic
{

    public int child_id { get; set; }
    public string child_firstname { get; set; }
    public string parent_surname { get; set; }
    public string club_name { get; set; }

}
 public class DetailsAccessLayer
{
    public static List<ChildBasic> GetAllChildBasicDetails()
    {
        List<ChildBasic> listChild = new List<ChildBasic>();
        string CS = ConfigurationManager.ConnectionStrings["dbyouthworkConnectionString"].ConnectionString;
        using (MySqlConnection con = new MySqlConnection(CS))
        {
            var InnerJoinClub = "SELECT child_details.child_id, child_details.child_firstname,child_details.parent_surname, enrolment_details.club_name FROM child_details INNER JOIN enrolment_details ON child_details.child_id = enrolment_details.child_id";
            MySqlCommand cmd = new MySqlCommand(innerJoinClub, con);
            con.Open();
            MySqlDataReader rdr = cmd.ExecuteReader();
            while (rdr.Read())
            {
                ChildBasic childbasic = new ChildBasic();
                childbasic.child_id = Convert.ToInt32(rdr["child_id"]);
                childbasic.child_firstname = rdr["child_firstname"].ToString();
                childbasic.parent_surname = rdr["parent_surname"].ToString();
                childbasic.club_name = rdr["club_name"].ToString();

                listChild.Add(childbasic);
            }
        }
        return listChild;
    }

但每次运行程序时，我都会收到错误:System.Web.dll 中发生类型为“System.Web.HttpException”但未在用户代码中处理的异常

附加信息:在所选数据源中未找到名为“club_name”的字段或属性。

谁能告诉我代码中的错误以及如何更正它？

非常感谢

编辑:这是错误发生的地方

private void GridViewDataBind()
    {
        GridView1.DataSource = DetailsAccessLayer.GetAllChildBasicDetails();
        GridView1.DataBind();        }

在GridView1.DataBind()

Answer 1

在您的 SQL 查询中，您需要为 enrolment_details.club_name 提供别名，例如 enrolment_details.club_name AS club_name