在这段代码中,我试图测试这种检查数据的 boolean 方法。这个项目的目的是为我们的校园制作一个食品预算系统。在这个初级阶段,我设置了一个表,其中有一个 boolean 值来检测不同的选项。
<?php
$db_host = "db4free.net";
$db_name = "testable";
$db_username = "muymuy1";
$db_password = "Muymuy2002";
$db = new PDO("mysql:host=$db_host; dbname=$db_name; charset=utf8", "$db_username", "$db_password") or die("error");
$sql = "INSERT INTO `food` (name, id, price, isForSingle, isForPair, isForSharing, isFullMeal) VALUES ('Sanwhich 234', NULL, 110, 1, 0, 0, 0)";
$db->query($sql) or die("Something happened");
$sql = "DELETE FROM `food` WHERE name LIKE '%sanwhich%'";
$stmt = $db->query($sql) or die("error 4");
$sql = "SELECT * FROM `food` WHERE isForSingle=0";
$stmt = $db->query($sql) or die("error 5");
$data = array();
$count = 0;
if($stmt !== false)
{
while($row = $stmt->fetch(PDO::FETCH_ASSOC))
{
$data[$count] = array(
"id" => $row['id'],
"name" => $row['name'],
"price" => $row['price'],
"isFullMeal" => $row['isFullMeal'],
"isForSharing" => $row['isForSharing'],
"isForPair" => $row['isForPair'],
"isForSingle" => $row['isForSingle'],
);
$count += 1;
}
}
echo '<pre>'; print_r($data); echo '</pre>';
?>
表数据:
但是,我的问题是这不起作用。 0与1混淆,1与0混淆,因为当我用WHERE isForPair = 0
搜索时,出现的是有1的数据行,而当我搜索WHERE isForPair = 1
,出现的是有0的数据行。
1) ... WHERE isForPair = 0 (Output: Results that isForPair = 1)
2) ... WHERE isForPair = 1(输出:无,尽管表中的所有内容都是 isForPair = 1)
最佳答案
您的表 (CREATE TABLE
) 语句的 DDL 语句必须与查询匹配。似乎您想将表中的数据与 boolean 值匹配。在这种情况下,您可以将字段 isForSingle
设置为数据库中的 TINYINT
数据类型。
注意 BOOLEAN
和TINYINT
是一样的 in MySQL RDBMS.
这是我试过的DDL语句。
CREATE TABLE food (id INTEGER, name VARCHAR(100), isForSingle TINYINT);
然后,我插入 2 条记录。
INSERT INTO food VALUES(1,'Hamburger',1);
INSERT INTO food VALUES(2,'Pizza',0);
然后,我尝试使用您的 PHP 代码查询数据。
<?php
$db_host = "YOURDBHOST";
$db_name = "YOURDATABASE";
$db_username = "YOURUSERNAME";
$db_password = "YOURPASSWORD";
$db = new PDO("mysql:host=$db_host; dbname=$db_name; charset=utf8", "$db_username", "$db_password") or die("error");
// ------------------------------------------------------------------
$sql = "SELECT * FROM `food` WHERE isForSingle=1";
$stmt = $db->query($sql) or die("error");
$data = array();
$count = 0;
if($stmt !== false)
{
while($row = $stmt->fetch(PDO::FETCH_ASSOC))
{
$data[$count] = array(
"id" => $row['id'],
"name" => $row['name'],
"isForSingle" => $row['isForSingle'],
);
$count += 1;
}
}
var_dump($data);
// -----------------------------------------------------------------
// ------------------------------------------------------------------
$sql = "SELECT * FROM `food` WHERE isForSingle=0";
$stmt = $db->query($sql) or die("error");
$data = array();
$count = 0;
if($stmt !== false)
{
while($row = $stmt->fetch(PDO::FETCH_ASSOC))
{
$data[$count] = array(
"id" => $row['id'],
"name" => $row['name'],
"isForSingle" => $row['isForSingle'],
);
$count += 1;
}
}
var_dump($data);
// ------------------------------------------------------------------
结果如下。
array(1) {
[0] =>
array(3) {
'id' =>
string(1) "1"
'name' =>
string(9) "Hamburger"
'isForSingle' =>
string(1) "1"
}
}
array(1) {
[0] =>
array(3) {
'id' =>
string(1) "2"
'name' =>
string(5) "Pizza"
'isForSingle' =>
string(1) "0"
}
}
希望对您有所帮助。
关于php - 由于错误的 1 和 0,SQL 得到相反的结果,反之亦然,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/38292212/