我是一个新手,我正在尝试使用 PHP 和 Mysql 创建一个登录系统。完成注册表并添加几个用户后,我试图创建一个登录表单。但它总是返回错误,说我的您的用户名或密码不正确!
。下面是我的代码。如果有人可以帮助我,那就太好了。如果我的怀疑太基本了,请提前道歉:/
<?php
session_start();
include '.\includes\functions\db.php';
?>
<?php
$username = strtolower(mysqli_real_escape_string($db, $_POST['username']));
$password = strtolower(mysqli_real_escape_string($db, $_POST['password']));
$sql = "SELECT * FROM users WHERE username = '$username' ";
$result = mysqli_query($db, $sql);
$row = mysqli_fetch_assoc($result);
$hash_pwd = $row['password'];
echo $hash_pwd;
echo $password;
$hash = password_verify($password, $hash_pwd);
if ($hash ==0) {
header("Location: ./index.php?error=check");
exit();
}else {
$sql = "SELECT * FROM user WHERE username = '$username' AND password = '$hash_pwd'";
$result = mysqli_query($db, $sql);
if (mysqli_num_rows($result) == 0) {
echo "Your username or password is incorrect!";
}else {
$_SESSION['id'] = $row['id'];
$_SESSION['username'] = $row['username'];
}
//header("Location: ./index.php");
}
?>
我的注册页面如下
<?php
//This Page is for registration of users
?>
<?php
// this php tag is for all includes
include '.\includes\functions\db.php';
?>
<?php
//print isset($_POST["submit"]);
//Getting all details inserted in form
if(isset($_POST["register"])){
$username = $_POST['username'];
$firstname = $_POST['firstname'];
$lastname = $_POST['lastname'];
$email = $_POST['email'];
$password = $_POST['password'];
$date = date('Y-m-d H:i:s');
//Encrypting and Securing recieved data
$username = strtolower(mysqli_real_escape_string($db, $username));
$firstname = strtolower(mysqli_real_escape_string($db, $firstname));
$lastname = strtolower(mysqli_real_escape_string($db, $lastname));
$email = strtolower(mysqli_real_escape_string($db, $email));
$password = strtolower(mysqli_real_escape_string($db, $password));
$encryptedpassword = password_hash($password, PASSWORD_DEFAULT);
//To check duplication of email ids
$sql = "SELECT email FROM users WHERE email='$email'";
$result = mysqli_query($db, $sql);
$row = mysqli_num_rows($result);//$row will return count of rows if any duplicate email ids are found
//To check duplication of usernames
$sql2 = "SELECT username FROM users WHERE username='$username'";
$result2 = mysqli_query($db, $sql2);
$row2 = mysqli_num_rows($result2);//$row2 will return count of rows if any duplicate usernames are found
//conditions to check what all duplicates are found
if($row > 0 && $row2 >0){
echo "Sorry...This email id and username is already taken!!!";
} elseif ($row > 0 ) {
echo "Sorry...This email id is already taken!";
} elseif ($row2 > 0) {
echo "Sorry...This Username is already taken!";
}else {
$query = mysqli_query($db, "INSERT INTO users (username, firstname, lastname, password, email, regdate) VALUES
('$username', '$firstname', '$lastname', '$encryptedpassword', '$email', '$date')");
if($query){
echo "Thank You! you are now registered.";
}
}
}
?>
最佳答案
我的代码中的错误是因为我的 where 子句中的 password = '$hash_pwd' 条件。当我使用给定的用户名重试行并稍后使用 php 验证密码时,它按预期工作。我猜想在 php 中使用 password_hash() 散列的密码不能像加密一样被检索和验证。无论如何,感谢您的所有回复
关于php - password_verify() 总是返回 false,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/40637613/