我正在尝试从 json 中获取数据,我想将其保存在数据库中。 我有错误,请帮我接通。下面是我的代码。
<?php
//My connection was ok
//read the json file contents
$url = ('http://api.football-data.org/v1/teams/61/players/');
$jsondata = file_get_contents($url);
//convert json object to php associative array
$data = json_decode($jsondata, true);
//print_r($data);
//get the employee details
foreach ($data['_links']['players'] as $myp) {
$name = $myp['name'];
$posi = $myp['position'];
$nation = $myp['nationality'];
$market = $myp['marketValue'];
}
// //insert into mysql table
mysql_select_db($db, $conn); //database and connection
$date = date('Y-m-d H:m:s'); //date stamp formatting
//sql query that insert the user info into the database
$sql = "INSERT INTO player ( Name, Position, Nationality, Market, Created)
VALUES( ?,?,?,?,?)";
// bind variables to insert query params
mysqli_stmt_bind_param($sql, 'sss', $name, $posi, $nation, $market, $date);
//if the connection is sucessful, display regards message
if (mysql_query($sql, $conn)) {
echo "Thank you <br/>";
} else { //if the connection is not established
die('Error: ' . mysql_error());
}
mysql_close($conn); //close of process or connection
?>
我尝试先打印我想要的值/数据,以确保 foreach 循环正常工作,但我也遇到了错误:
注意:Undefined index: players in C:\xampp\htdocs\lab4\apitest.php on line 22
警告:第 22 行为 C:\xampp\htdocs\lab4\apitest.php 中的 foreach() 提供的参数无效
警告:mysql_select_db() 期望参数 2 是第 31 行 C:\xampp\htdocs\lab4\apitest.php 中给出的资源、对象
警告:mysqli_stmt_bind_param() 期望参数 1 为 mysqli_stmt,第 38 行 C:\xampp\htdocs\lab4\apitest.php 中给出的字符串
警告:mysql_query() 期望参数 2 是第 40 行 C:\xampp\htdocs\lab4\apitest.php 中给出的资源、对象 错误:
这是我的 json:
{
"_links": {
"self": {
"href": "http://api.football-data.org/v1/teams/61/players"
},
"team": {
"href": "http://api.football-data.org/v1/teams/61"
}
},
"count": 25,
"players": [
{
"name": "Marcos Alonso",
"position": "Left-Back",
"jerseyNumber": 3,
"dateOfBirth": "1990-12-28",
"nationality": "Spain",
"contractUntil": "2021-06-30",
"marketValue": "9,000,000 €"
},
{
"name": "Marco van Ginkel",
"position": "Central Midfield",
"jerseyNumber": null,
"dateOfBirth": "1992-12-01",
"nationality": "Netherlands",
"contractUntil": "2018-06-30",
"marketValue": "7,000,000 €"
},
请帮助我了解如何成功读取所需数据并将其存储在数据库中。
非常感谢!
最佳答案
您的数据访问方法有问题。你写:
foreach ($data['_links']['players'] as $myp) {
你必须改成这样才能得到正确的结构:
foreach ($data['players'] as $myp) {
因为 players 键不是 _links 的子键。
第二个问题是如果你想将所有玩家插入数据库。您必须将语句移动并插入并执行到 foreach 循环中。
希望对你有帮助!
关于php - 如何抓取json数据并存入数据库,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/43133080/