如何在 CodeIgniter 中内爆并将值插入数据库?
我正在使用 CodeIgniter 框架创建多项选择测验脚本。我想像这样存储用户结果:
id userid q_id answer_id time_taken
1 1 1,2,3,4,5 2,3,4,5,3 4,5,7,6,7
在我的 Controller 中:
public function insert_result()
{
$this->load->model('quiz_models');
$user_id=$this->input->post('user_id');
$qq_id=$this->input->post('questionid');
$answer_id=$this->input->post('AnswerID');
$time_taken=$this->input->post('timetaken');
$question_no=$this->input->post('question_no');
$bd = "$question_no";
switch ($bd) {
case"1":
$data=array('user_id'=>$user_id,
'q_id'=>$qq_id,
'answer_id'=>$answer_id,
'time_taken'=>$time_taken);
$this->quiz_models->insert_result($data);
break;
case"2":
quiz_test();
break;
case"3":
quiz_test();
break;
case"4":
quiz_test();
break;
case"5":
quiz_test();
$this->session->unset_userdata('lastids');
break;
default:
echo "something is wrong";
}
}
public function quiz_test()
{
$this->load->model('quiz_models');
$quiz=$this->quiz_models->quiz_test();
foreach($quiz as $row){
$qid=$row->q_id;
$ans=$row->answer_id;
$time=$row->time_taken;
$a = array("$qq_id","$qid");
$b = array("$answer_id","$ans");
$c = array("$time_taken","$time");
$comma = implode(",",$a);
$comma1 = implode(",",$b);
$comma2 = implode(",",$c);
$data=array('q_id'=>$comma,
'answer_id'=>$comma1,
'time_taken'=>$comma2);
$this->quiz_model->update_result($data);
}
}
}
和模型:
function insert_result($data)
{
$this->dbb->insert('results',$data);
$sectio=$this->db->insert_id();
$this->session->set_userdata('lastids',$sectio);
}
function quiz_test()
{
$ses_id = $this->session->userdata('lastids');
$sql = "SELECT q_id, answer_id, time_taken FROM results WHERE id='$ses_id'";
$query = $this->dbb->query($sql);
$result = $query->result();
return $result;
}
function update_result($data){
$ses_id = $this->session->userdata('lastids');
$this->db->where('id',$ses_id);
$this->db->update('results',$data);
}
当我运行它时没有任何反应,没有显示任何错误,我错在哪里了?
请帮助我我做错了什么
最佳答案
首先 - 我认为您的数据库结构存在重大问题
Normalize your Data
You should prevent to store your information in the table like that. It should be possible to normalize your data properly. If you dont know how to do that the following link could be interesting:
然而,一个可能的解决方案是构建您的数据:
为了做到这一点 - 在您的模型中创建一个保存方法以在更新和插入之间进行拆分 - 这个模型看起来像
class Quiz_Models
{
private $arrPostData;
public function save($arrPostData = false)
{
$this->arrPostData = (!$arrPostData) ? $this->input->post() : $arrPostData;
$id = $this->session->userdata("lastids");
if ($id)
{
$query = $this->db
->select("*")
->from("results")
->where("id",$id)
->get();
if ($query->num_rows() == 1)
{
$this->update($query->row(0));
}
else return false;
}
else
{
$this->insert();
}
if ($this->arrPostData['question_no'] == 10) $this->session->unset_userdata("lastids");
}
private function update($objData)
{
$objCollection = new Quiz_Collection();
$objCollection->userId = $objData->userid;
$objCollection->id = $objData->id;
$arrData = explode($objData->q_id);
foreach($arrData AS $key => $quizId)
{
$objQuiz = new stdClass();
$objQuiz->q_id = $quizId;
$objQuiz->answer_id = explode($objData->answer_id)[$key];
$objQuiz->time_taken = explode($objData->answer_id)[$key];
$objCollection->append($objQuiz);
}
$objQuizFromPost = new stdClass();
$objQuizFromPost->q_id = $this->arrPostData["questionid"];
$objQuizFromPost->answer_id = $this->arrPostData['AnswerID'];
$objQuizFromPost->time_taken = $this->arrPostData['timetaken'];
$objCollection->addQuizFromPost($objQuizFromPost);
$this->db
->where("id",$objCollection->id)
->update("results",$objCollection->getDbData());
}
private function insert()
{
$objCollection = new Quiz_Collection();
$objCollection->userId = $this->arrPostData['user_id'];
$objQuizFromPost = new stdClass();
$objQuizFromPost->q_id = $this->arrPostData["questionid"];
$objQuizFromPost->answer_id = $this->arrPostData['AnswerID'];
$objQuizFromPost->time_taken = $this->arrPostData['timetaken'];
$objCollection->addQuizFromPost($objQuizFromPost);
$this->db->insert("results",$objCollection->getDbData());
$this->session->set_userdata("lastids", $this->db->insert_id());
}
}
作为补充,你需要一个集合对象(把它放在你的模型下面)
class Quiz_Collection extends Array_Object
{
public $userId = 0;
public $id = 0;
public function addQuizFromPost($objQuiz)
{
if (intval($objQuiz->q_id) > 0)
{
foreach($this AS $key => $obj)
{
if ($obj->q_id == $objQuiz->q_id)
{
$this->offsetSet($key, $objQuiz);
return true;
}
}
$this->append($objQuiz);
return true;
}
return false;
}
public function sortQuizData($objA, $objB)
{
if ($objA->q_id == $objB->q_id) return 0;
return ($objA->q_id < $objB->q_id) ? -1 : 1;
}
public function getDbData()
{
$this->uasort(array($this,"sortQuizData"));
$arrData = $this->getArrayCopy();
$arrDbData = [
"userid" => $this->userId,
"q_id" => implode(array_map(function($obj){ return $obj->q_id;},$arrData),","),
"answer_id" => implode(array_map(function($obj){ return $obj->answer_id;},$arrData),","),
"time_taken" => implode(array_map(function($obj){ return $obj->time_taken;},$arrData),","),
];
return $arrDbData;
}
}
pS:这只是说明如何以正确的方式做到这一点。请研究这段代码。如果您仍然不明白发生了什么,请随时提问。
关于php - 如何在 codeigniter 中将值内爆并插入到数据库中?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/43199448/