mysql - 更新表上的 370 条记录，同时为 where 语句内部连接到另一个表

Question

好吧，我是 SQL 的新手，我正在尝试编写一个查询，以在 officeid=10 的情况下将数字 2 替换为数字 4，所以我现在拥有的是以下内容。一个表称为 Carer_Supervisions，它通过辅助键链接到另一个表，officeid 在另一个名为 carer_information 的表上。

SELECT Carer_Supervisions.SupervisionID
    ,Carer_Supervisions.RegionID
    ,Carer_Supervisions.Date_Created
    ,Carer_Supervisions.Created_By
    ,Carer_Supervisions.Complete
    ,Carer_Supervisions.Completed_Date
    ,Carer_Supervisions.Completed_By
    ,Carer_Supervisions.CarerID
    ,Carer_Supervisions.Visit_Date
    ,Carer_Supervisions.SSW
    ,Carer_Supervisions.Location
    ,Carer_Supervisions.Present
    ,Carer_Supervisions.Child1
    ,Carer_Supervisions.Child2
    ,Carer_Supervisions.Child3
    ,Carer_Supervisions.Child4
    ,Carer_Supervisions.Child5
    ,Carer_Supervisions.Child6
    ,Carer_Supervisions.Child7
    ,Carer_Supervisions.Child8
    ,Carer_Supervisions.Caring_for_Children
    ,Carer_Supervisions.Education
    ,Carer_Supervisions.Working_Team
    ,Carer_Supervisions.Training_and_Development
    ,Carer_Supervisions.Environment
    ,Carer_Supervisions.Concerns
    ,Carer_Supervisions.Personal
    ,Carer_Supervisions.Agency
    ,Carer_Supervisions.Day_Care
    ,Carer_Supervisions.Manager
    ,Carer_Supervisions.Carer_Signed
    ,Carer_Supervisions.Cancelled
    ,Carer_Supervisions.Cancel_Reason
    ,Carer_Supervisions.Signed_Sent
    ,Carer_Information.OfficeID
FROM Carer_Supervisions
INNER JOIN Carer_Information ON Carer_Supervisions.CarerID = Carer_Information.CarerID

UPDATE Carer_supervisions
SET RegionID = REPLACE(RegionID, '2', '4')
WHERE (Carer_Information.OfficeID = 10)

这是对的还是需要修改？

Answer 1

这样你就可以更新了。

UPDATE CS SET RegionID= REPLACE(RegionID, '2', '4')
FROM Carer_Supervisions CS 
INNER JOIN Carer_Information CI ON CS.CarerID = CI.CarerID
WHERE CI.OfficeID = 10

试试这个:

UPDATE Carer_Supervisions SET Carer_Supervisions.RegionID= REPLACE(CS.RegionID, '2', '4')
FROM Carer_Supervisions CS 
INNER JOIN Carer_Information CI ON CS.CarerID = CI.CarerID
WHERE CI.OfficeID = 10