我想要的是从 Android 中的编辑文本中插入一个值到 mysql 数据库中,有人可以用一个简单的例子告诉我怎么做吗? mysqldb 名称是 'android' 包含 1 列 'name'
<EditText
android:layout_width="250dp"
android:layout_height="wrap_content"
android:hint="User Name"
android:id="@+id/new_user_name"
android:layout_gravity="center_horizontal"
android:layout_marginTop="20dp"/>
最佳答案
首先我们将连接到数据库
<?php
define('HOST','yourHost');
define('USER','username');
define('PASS','password');
define('DB','android');
$con = mysqli_connect(HOST,USER,PASS,DB);
然后您需要捕获 post 变量。此变量将与我们的应用一起发送。
$name = $_POST['name'];
现在将值插入您的数据库。
$sql = "insert into Persons (name,address) values ('$name')";
if(mysqli_query($con,$sql)){
echo 'success';
}
else{
echo 'failure';
}
mysqli_close($con);
?>
我使用 EditText
和 Button
创建了一个简单的布局:
activity_main.xml
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
xmlns:tools="http://schemas.android.com/tools"
android:layout_width="match_parent"
android:layout_height="match_parent"
android:orientation="vertical"
android:padding="10dp"
tools:context=".MainActivity">
<TextView
android:id="@+id/textView"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:text="Name" />
<EditText
android:id="@+id/editTextName"
android:layout_width="match_parent"
android:layout_height="wrap_content" />
<Button
android:id="@+id/button"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:onClick="insert"
android:text="Insert" />
<TextView
android:id="@+id/textViewResult"
android:layout_width="wrap_content"
android:layout_height="wrap_content" />
MainActivity.java
public class MainActivity extends ActionBarActivity {
private EditText editTextName;
private EditText editTextAdd;
String name = editTextName.getText().toString();
String add = editTextAdd.getText().toString();
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
editTextName = (EditText) findViewById(R.id.editTextName);
}
public void insert(View view){
insertToDatabase(name,add);
}
private void insertToDatabase(final String name, final String add){
class SendPostReqAsyncTask extends AsyncTask<String, Void, String> {
@Override
protected String doInBackground(String... params) {
String paramUsername = params[0];
List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>();
nameValuePairs.add(new BasicNameValuePair("name", name));
nameValuePairs.add(new BasicNameValuePair("address", add));
try {
HttpClient httpClient = new DefaultHttpClient();
HttpPost httpPost = new HttpPost(
"http://youwebsite.com/insert-db.php");
httpPost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
HttpResponse response = httpClient.execute(httpPost);
HttpEntity entity = response.getEntity();
} catch (ClientProtocolException e) {
} catch (IOException e) {
}
return "success";
}
@Override
protected void onPostExecute(String result) {
super.onPostExecute(result);
Toast.makeText(getApplicationContext(), result, Toast.LENGTH_LONG).show();
TextView textViewResult = (TextView) findViewById(R.id.textViewResult);
textViewResult.setText("Inserted");
}
}
SendPostReqAsyncTask sendPostReqAsyncTask = new SendPostReqAsyncTask();
sendPostReqAsyncTask.execute(name, add);
}
@Override
public boolean onCreateOptionsMenu(Menu menu) {
// Inflate the menu; this adds items to the action bar if it is present.
//getMenuInflater().inflate(R.menu.menu_main, menu);
return true;
}
@Override
public boolean onOptionsItemSelected(MenuItem item) {
// Handle action bar item clicks here. The action bar will
// automatically handle clicks on the Home/Up button, so long
// as you specify a parent activity in AndroidManifest.xml.
//int id = item.getItemId();
//noinspection SimplifiableIfStatement
//if (id == R.id.action_settings) {
// return true;
//}
return super.onOptionsItemSelected(item);
}
}
希望这能帮助您更好地理解它。
关于php - 将编辑文本值从 android 插入到 mysql,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/43837693/