java - 如何从 Java 控制台应用程序中的扫描器读取字符串？

Question

import java.util.Scanner;
class MyClass
{
    public static void main(String args[])
    {
        Scanner scanner = new Scanner(System.in);
        int employeeId, supervisorId;
        String name;
        System.out.println("Enter employee ID:");
        employeeId = scanner.nextInt();
        System.out.println("Enter employee name:");
        name = scanner.next();
        System.out.println("Enter supervisor ID:");
        supervisorId = scanner.nextInt();
    }
}

我在尝试输入名字和姓氏时遇到此异常。

Enter employee ID:
101
Enter employee name:
firstname lastname
Enter supervisor ID:
Exception in thread "main" java.util.InputMismatchException
    at java.util.Scanner.throwFor(Unknown Source)
    at java.util.Scanner.next(Unknown Source)
    at java.util.Scanner.nextInt(Unknown Source)
    at java.util.Scanner.nextInt(Unknown Source)
    at com.controller.Menu.<init>(Menu.java:61)
    at com.tests.Employeetest.main(Employeetest.java:17)

但如果我只输入名字，它会继续工作。

Enter employee ID:
105
Enter employee name:
name
Enter supervisor ID:
501

我想要的是读取完整的字符串，无论它是作为 name 还是 firstname lastname 给出的。这里有什么问题？

Answer 1

Scanner scanner = new Scanner(System.in);
int employeeId, supervisorId;
String name;
System.out.println("Enter employee ID:");
employeeId = scanner.nextInt();
scanner.nextLine(); //This is needed to pick up the new line
System.out.println("Enter employee name:");
name = scanner.nextLine();
System.out.println("Enter supervisor ID:");
supervisorId = scanner.nextInt();

调用 nextInt() 是一个问题，因为它没有选择新行(当您按下回车键时)。因此，在此之后调用 scanner.nextLine() 即可。