mysql - 使用 all 运算符选择子查询而不加入 mysql

Question

我需要显示部门 1 的所有 worker 的 ID、姓名和出生日期，这些 worker 比部门 2 的 worker 年轻。我正在尝试不加入。

这就是我现在所拥有的，当我运行它时它并没有失败，但它显示了部门 2 的所有 worker ，无论他们的生日如何。

SELECT ID, CONCAT(fName," " ,lName) AS "Worker Name", dob
FROM Worker
WHERE dob <= ALL (SELECT department
FROM Worker
WHERE deparment = 1 
)
AND deparment = 2;

Answer 1

你想检查 dob 然后你应该选择 dob

  SELECT ID, CONCAT(fName," " ,lName) AS "Worker Name", dob
  FROM Worker
  WHERE dob <= ALL (SELECT dob
  FROM Worker
  WHERE deparment = 1 
  )
  AND deparment = 2;