MYSQL - 获取一个表中的行在另一个表中有多个行

Question

我在一个数据库中有 3 个表:

属性表:

+-------------+--------------------+
| property_id | property_reference |
+-------------+--------------------+
|           1 | RA123              |
|           4 | RT123              |
+-------------+--------------------+

特征表:

+------------+--------------+
| feature_id | feature_name |
+------------+--------------+
|          1 | pool         |
|          2 | garden       |
|          3 | wine house   |
|          4 | parking      |
+------------+--------------+

还有一张表 properties_features:

+-------------+------------+
| property_id | feature_id |
+-------------+------------+
|           1 |          1 |
|           1 |          2 |
|           1 |          4 |
|           4 |          1 |
|           4 |          2 |
|           4 |          3 |
+-------------+------------+

例如，我想检索只有游泳池和花园的属性 ID

Answer 1

select distinct property_id  from properties_features
where feature_id  IN (1,2) and property_id  in(select property_id  from properties_features where feature_id  IN(1,2) group by property_id  having COUNT(property_id ) > 1)
order by property_id 

这将获取所有具有游泳池和花园但没有任何连接或硬编码数据的属性 ID。

如果更改了任何 feature_name，这也会在将来帮助您，例如:from pool -> Pool。这个查询仍然有效! :)

对于更动态的查询，最好不要使用任何硬编码值。