php - 获取为每个选项创建的 Select 标签，而不是为所有选项创建一个标签

Question

我的 select 获取所有数据，然后在单独的下拉列表中显示所有数据

问题:如何在同一个下拉列表中获取所有值？

<?php
$servername = "localhost";
$username = "root";
$password = "";
$dbname = "categorys";

// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
    die("Connection failed: " . $conn->connect_error);
} 

$sql = "SELECT * FROM all_category";
$result = $conn->query($sql);

if ($result->num_rows > 0) {
    while($row = mysqli_fetch_array( $result )) {
        echo "<select>";
        echo '<option>' . $row['category'] . '</option>';
        echo "</select>";
    }
}
?>

Answer 1

让你的 select 标签脱离循环，只使用 option 标签:

if ($result->num_rows > 0) {
    echo "<select>";
    while($row = mysqli_fetch_array( $result )) {
        echo '<option>' . $row['category'] . '</option>';
    }
    echo "</select>";
}

此外，缩进代码会使其看起来更好。