所以我想将数据从表单(而不是填写表单)输入到数据库表中。之后我想将输入与某个表(表 A)匹配以获取输入数据的 ID。然后我想将该 ID 插入到另一个表中......
<?php
//submit attendance mahasiswa
if(isset($_POST['buttonSubmitAbsenMahasiswa'])){
foreach($_POST['inputStatusAbsen'] as $id_absensi=>$status_absensi){
$id_mahasiswa = $_POST['inputHiddenIDMahasiswa'][$id_absensi];
$nim_mahasiswa = $_POST['inputHiddenNIMMahasiswa'][$id_absensi];
$nama_mahasiswa = $_POST['inputHiddenNamaMahasiswa'][$id_absensi];
$nama_matakuliah = $_POST['inputHiddenMataKuliahMahasiswa'][$id_absensi];
$tanggal_absensi = date("Y-m-d");
//get matakuliah id
$class_query = "SELECT * FROM matakuliah WHERE nama_matakuliah='".$nama_matakuliah."'";
$class_id = mysqli_query($connection, $class_query);
if($class_id){
while($class_id1 = $class_id->fetch_assoc()){
$class_id_fin = $class_id1['id_matakuliah'];
}
}
//get mahasiswa id
$student_query = "SELECT * FROM data_mahasiswa WHERE nama_mahasiswa='".$nama_mahasiswa."'";
$student_id = mysqli_query($connection, $student_query);
if($student_id) {
while ($student_id1 = $student_id->fetch_assoc()) {
$student_id_fin = $student_id1['id_mahasiswa'];
}
}
//insert or update the record
$query_insert_data_absensi = "INSERT INTO data_absensi VALUES ('$class_id_fin' , '$student_id_fin' , '$tanggal_absensi' , '$status_absensi')";
mysqli_query($connection, $query_insert_data_absensi);
}
}
?>
我想将输入的数据匹配到:
CREATE TABLE data_mahasiswa(
id_mahasiswa int(255) PRIMARY KEY AUTO_INCREMENT,
nim_mahasiswa varchar(255),
nama_mahasiswa varchar(255),
matakuliah_mahasiswa varchar(255));
或在这里:
CREATE TABLE matakuliah(
id_matakuliah int(255) PRIMARY KEY AUTO_INCREMENT,
nama_matakuliah varchar(255));
这样我就可以得到对应表的id
然后我想将 id 插入到:
CREATE TABLE data_absensi(
id_absensi int(255) PRIMARY KEY AUTO_INCREMENT,
id_mahasiswa int(255),
id_matakuliah int(255),
tanggal_absensi date,
status_absensi varchar(255));
输入是这样的:
<tr>
<td>
<?php echo $class['id_mahasiswa']; ?>
<input type="text" hidden value="<?php echo $class['id_mahasiswa']; ?>" id="inputHiddenIDMahasiswa" name="inputHiddenIDMahasiswa[<?php echo $i; ?>]">
</td>
<td>
<?php echo $class['nim_mahasiswa']; ?>
<input type="text" hidden value="<?php echo $class['nim_mahasiswa']; ?>" id="inputHiddenNIMMahasiswa" name="inputHiddenNIMMahasiswa[<?php echo $i; ?>]">
</td>
<td>
<?php echo $class['nama_mahasiswa']; ?>
<input type="text" hidden value="<?php echo $class['nama_mahasiswa']; ?>" id="inputHiddenNamaMahasiswa" name="inputHiddenNamaMahasiswa[<?php echo $i; ?>]">
</td>
<td>
<?php echo $class['matakuliah_mahasiswa']; ?>
<input type="text" hidden value="<?php echo $class['matakuliah_mahasiswa']; ?>" id="inputHiddenMataKuliahMahasiswa" name="inputHiddenMataKuliahMahasiswa[<?php echo $i; ?>]">
</td>
<td>
<div class="form-check form-check-inline">
<input class="form-check-input" type="radio" name="inputStatusAbsen[<?php echo $i; ?>]" value="Hadir">
<label class="form-check-label" for="inlineRadio1">Hadir</label>
</div>
<div class="form-check form-check-inline">
<input class="form-check-input" type="radio" name="inputStatusAbsen[<?php echo $i; ?>]" value="Tidak hadir">
<label class="form-check-label" for="inlineRadio2">Tidak Hadir</label>
</div>
</td>
</tr>
我哪里错了? p.s 对非英语变量感到抱歉:|
最佳答案
所以在看到类似的问题后,我终于找到了解决问题的方法 right here
我把我的输入改成这样:
<?php
$i = 0;
while($row = mysqli_fetch_array($result_pencarian)){
?>
<tr>
<td>
<?php echo $row['id_mahasiswa']; ?>
<input type="text" hidden value="<?php echo $row['id_mahasiswa']; ?>" id="inputHiddenIDMahasiswa" name="inputHiddenIDMahasiswa[<?php echo $i; ?>]"/>
</td>
<td>
<?php echo $row['nim_mahasiswa']; ?>
<input type="text" hidden value="<?php echo $row['nim_mahasiswa']; ?>" id="inputHiddenNIMMahasiswa" name="inputHiddenNIMMahasiswa[<?php echo $i; ?>]"/>
</td>
<td>
<?php echo $row['nama_mahasiswa']; ?>
<input type="text" hidden value="<?php echo $row['nama_mahasiswa']; ?>" id="inputHiddenNamaMahasiswa" name="inputHiddenNamaMahasiswa[<?php echo $i; ?>]"/>
</td>
<td>
<?php echo $row['matakuliah_mahasiswa']; ?>
<input type="text" hidden value="<?php echo $row['matakuliah_mahasiswa']; ?>" id="inputHiddenMataKuliahMahasiswa" name="inputHiddenMataKuliahMahasiswa[<?php echo $i; ?>]"/>
</td>
<td>
<div class="form-check form-check-inline">
<input class="form-check-input" type="radio" checked="checked" name="inputStatusAbsen[<?php echo $i; ?>]" value="Hadir"/>
<label class="form-check-label" for="inlineRadio1">Hadir</label>
</div>
<div class="form-check form-check-inline">
<input class="form-check-input" type="radio" name="inputStatusAbsen[<?php echo $i; ?>]" value="Tidak hadir"/>
<label class="form-check-label" for="inlineRadio2">Tidak Hadir</label>
</div>
</td>
</tr>
<?php
$i++;
}?>
其余的php都是一样的
关于php - 从表中获取值并将该值提交到另一个表 mysql php,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/55196126/