php - 如何在 2 表中更新？ (t_judul 和 mahasiswa 中的 id_status)

Question

我尝试在 t_judul 和 mahasiswa 上更新 id_status 并将我的数据保存在 t_jadwal 上，所以我尝试了这段代码

Sql 在t_judul 上成功保存数据 但是 sql2 和 sql3 无法将表 t_judul 和 mahasiswa 中的 id_status 更新为 54

我的模型

public function simpanjadwal($post,$id_judul){
        $id_judul          = $this->db->escape($post['id_judul']);
        $id_status          = $this->db->escape($post['id_status']);
        $judul          = $this->db->escape($post['judul']);
        $topik               = $this->db->escape($post['topik']);
        $nim               = $this->db->escape($post['nim']);
        $nama_awal               = $this->db->escape($post['nama_awal']);
        $nama_akhir               = $this->db->escape($post['nama_akhir']);
        $pbb1               = $this->db->escape($post['pbb1']);
        $pbb2               = $this->db->escape($post['pbb2']);
        $pgj1               = $this->db->escape($post['pgj1']);
        $pgj2           = $this->db->escape($post['pgj2']);
        $waktuujian           = $this->db->escape($post['waktuujian']);
        $tempatujian               = $this->db->escape($post['tempatujian']);

        $sql = $this->db->query("INSERT INTO t_jadwal (
                    id_judul,
                    id_status,
                    judul,
                    topik,
                    nim,
                    nama_awal,
                    nama_akhir,
                    pbb1,
                    pbb2,
                    pgj1,
                    pgj2,
                    waktuujian,
                    tempatujian
                )
                VALUES
                    (
                    $id_judul,
                    $id_status,
                    $judul,
                    $topik,
                    $nim,
                    $nama_awal,
                    $nama_akhir,
                    $pbb1,
                    $pbb2,
                    $pgj1,
                    $pgj2,
                    $waktuujian,
                    $tempatujian
                                        )");
        $sql2  = $this->db->query("UPDATE mahasiswa, t_judul SET mahasiswa.id_status = 54 WHERE t_judul.nim = mahasiswa.nim AND t_judul.id_judul = ".intval($id_judul));
        $sql3  = $this->db->query("UPDATE t_judul,mahasiswa SET t_judul.id_status = 54 WHERE t_judul.nim = mahasiswa.nim AND t_judul.id_judul = ".intval($id_judul));

        return TRUE;
        }

我的 Controller

public function inputjadwalseminar($id_judul){
     $this->load->model("m_pkip");

     $data['list_judulseminar'] = $this->m_pkip->selectjudul($id_judul);
     $data['list_dosen'] = $this->m_pkip->load_dosen();
     if(isset($_POST['btnSimpanJadwal'])){
         $this->m_pkip->simpanjadwal($_POST, $id_judul);
         redirect("pkip");
     }
     $data['default'] = $this->m_pkip->get_default($id_judul);
     $this->load->view("pkip/v_inputjadwalseminar",$data);
 }

sql2 和 sql3 查询无法更新 t_judul 和 mahasiswa 中的 id_status 但数据成功保存在 t_jadwal 上

我尝试转储 sql2 和 sql3，结果是 bool(true) bool(true) 我试图转储 id_judul，它说 string(4)"72"*note 72 是 id_judul

Answer 1

解决了我把我的代码改成

$sql2  = $this->db->query("UPDATE mahasiswa, t_judul SET mahasiswa.id_status = 54 WHERE t_judul.nim = mahasiswa.nim AND t_judul.id_judul = $id_judul"); 

$sql3  = $this->db->query("UPDATE t_judul,mahasiswa SET t_judul.id_status = 54 WHERE t_judul.nim = mahasiswa.nim AND t_judul.id_judul = $id_judul");