javascript - 如何使用 QuillJs 和 body-parser 提交表单？

Question

我是 Nodejs(以及一般编码)的新手。我正在尝试构建一个小型内容管理系统。我希望我的潜在最终用户能够在单击按钮向我的博客提交帖子之前对其内容进行样式设置(粗体、斜体、超链接等)。有点像我在输入此内容时在 Stackoverflow 上看到的工具栏

以下是我阅读 Quill 指南后到目前为止得到的信息:

form.ejs

<style>
#editor {
  height: 300px;
}

</style>

<!-- Include Quill stylesheet -->
<link href="https://cdn.quilljs.com/1.0.0/quill.snow.css" rel="stylesheet">

<!-- Create the toolbar container -->
<div id="toolbar">
  <button class="ql-bold">Bold</button>
  <button class="ql-italic">Italic</button>
</div>

 <form action = '/blog' method = 'POST'>
  <!-- Create the editor container -->
  <input type = 'text' name = 'title' placeholder = 'title'>
  <label for="body">About me</label>
  <input name="body" type="hidden">
  <div id="editor">
     <p>I am at my wit's end. Stackoverflow is my last hope</p>
  </div>
    <button type="submit">Submit</button>

 </form>


<!-- Include the Quill library -->
<script src="https://cdn.quilljs.com/1.0.0/quill.js"></script>

<!-- Initialize Quill editor -->
<script>
  var editor = new Quill('#editor', {
    modules: { toolbar: '#toolbar' },
    theme: 'snow'
  });

  var form = document.querySelector('form');
  form.onsubmit = function() {
    console.log("hey")
    // Populate hidden form on submit
    var body = document.querySelector('input[name=body]');
    body.value = JSON.stringify(quill.getContents());

    console.log("Submitted", $(form).serialize(), $(form).serializeArray());

  };

</script> 

app.js 文件

var app             = require('express')(),
    mongoose        = require('mongoose'),
    Blog            = require('./model/blog'),
    bodyParser      = require('body-parser');

mongoose.connect("mongodb://localhost/quill_demo", {useMongoClient:true});    
app.set('view engine','ejs'); //EJS WILL BE THE DEFAULT FILE THAT DISPLAYS THE FRONT-END DATA
app.use(bodyParser.json());
app.use(bodyParser.urlencoded({extended:true})); // retrieve text from submitted forms from the EJS files. 

//Add new blog to the database
app.post('/blog', function(req, res){
    var myPost = {
        title:req.body.title,
        body: req.body.body
    };
    Blog.create(myPost, function(err, newBlog){
        if(err){
            console.log(err);
        } else {
            console.log("New Blog has been added");
            newBlog.save(function(err, savedBlog){
                if(err){
                    console.log(err);
                }else {
                    console.log(savedBlog);
                    res.redirect('/blog');
                }

            });
        }
    });

});

点击提交后我检查了数据库。 “标题”字段工作正常。但“body”字段中没有添加任何内容。

看来我缺少了一些东西。我将不胜感激任何帮助。如果有人只是在我的代码中添加缺少的部分，我不会介意，稍后我会从他们的步骤中学习。

附注我没有 CS 学位。靠我自己学习。因此，请尽可能使用通俗易懂的语言进行回答

Answer 1

没关系，我已经明白了!

我将脚本更改为这个，它对我有用。提交表单时调用该函数

<script>
  var editor = new Quill('#editor', {
      modules: { toolbar: "#toolbar" },
      theme: 'snow'
  });


  function formatField(){
    var editor = document.querySelector(".ql-editor").contentEditable = false;
    var clipboard = document.querySelector(".ql-clipboard").contentEditable = false;
    var bar = document.querySelector("input[type=text]").type="hidden"
    var p = document.querySelector("#editor");
    var myInput = document.querySelector("input[name=about]");
    myInput.value = p.innerHTML;
  }


</script>