javascript - 从最后一行删除谷歌电子表格中的重复行

Question

我在 google spraedsheet 中找到了删除重复行的代码: 从这个网址: https://developers.google.com/apps-script/articles/removing_duplicates

function removeDuplicates() {
  var sheet = SpreadsheetApp.getActiveSpreadsheet().getSheetByName('Sheet1');
  var data = sheet.getDataRange().getValues();
  var last=sheet.getLastRow();
  var newData = new Array();
  for(i in data){
    //Logger.log(i);
    var row = data[i];
    //Logger.log(row[5]);
    var duplicate = false;
    for(j in newData){
      //Logger.log(newData[j][5]);
      if(row[5] == newData[j][5]){
        duplicate = true;
      }
    }
    if(!duplicate){
      newData.push(row);
    }
  }
  sheet.clearContents();
  sheet.getRange(1, 1, newData.length, newData[0].length).setValues(newData);
}

但是这个函数开始从第一行删除重复行，我想从工作表的最后一行开始删除。 我该怎么做？

Answer 1

试试 JavaScript 数组 reverse() 方法。它在下面使用了两次:

function removeDuplicates() {
  var sheet = SpreadsheetApp.getActiveSpreadsheet().getSheetByName('Sheet1');
  var data = sheet.getDataRange().getValues();

  data.reverse(); //reverses the row order.

  var last=sheet.getLastRow();
  var newData = new Array();
  for(i in data){
    //Logger.log(i);
    var row = data[i];
    //Logger.log(row[5]);
    var duplicate = false;
    for(j in newData){
      //Logger.log(newData[j][5]);
      if(row[5] == newData[j][5]){
        duplicate = true;
      }
    }
    if(!duplicate){
      newData.push(row);
    }
  }

  newData.reverse(); // reverses your data back to its original order.

  sheet.clearContents();
  sheet.getRange(1, 1, newData.length, newData[0].length).setValues(newData);
}

如果成功了请告诉我。