javascript - google.visualisation 未使用 ajax 定义

Question

当我运行下面的代码时，我得到了 TypeError: google.visualisation is undefined[了解更多] 数据从我的 .php 文件返回，当我执行 console.log 时我可以看到它。 我可能迷失在回调中，或者也许有人可以用其他方式解决？

我尝试在执行 ajax 之前加载视觉效果 here但同样的错误。我也查看了其他可能的答案，但我仍然无法让它发挥作用。

这是我的代码:

$(document).ready(function(){

console.log("hello world")
//alert("result")

$.ajax({
    url:"data.php",
    dataType : "JSON",
    success : function(result) {
        google.charts.load('current', { 'packages':['corechart'] });
        google.charts.setOnLoadCallback(function() {
            console.log(result);
            drawChart(result);                  
        });
    }
}); 

function drawChart(result) {

    var data = new google.visualisation.Datatable();
    data.addColumn('string','Name');
    data.addColumn('number','Quantity');
    var dataArray=[];
    $.each(result, function(i, obj) {
        dataArray.push([ obj.name, parseInt(obj.quantity) ]);
    });

    data.addRows(dataArray);

    var piechart_options = {
        title : 'Pie Chart: How Much Products Sold By Last Night',
        width : 400,
        height : 300
    }
    var piechart = new google.visualisation.PieChart(document
            .getElementById('piechart_div'));
    piechart.draw(data, piechart_options)

    var barchart_options = {
        title : 'Bar Chart: How Much Products Sold By Last Night',
        width : 400,
        height : 300,
        legend : 'none'
    }
    var barchart = new google.visualisation.BarChart(document
            .getElementById('barchart_div'));               
    barchart.draw(data, barchart_options)
}           

}); 

我从我的数据库查询中得到一个对象，所以我认为那部分是正确的，它是一个包含 6 个对象的数组:

0: Object { id: "1", name: "Product1", quantity: "2" }
​1: Object { id: "2", name: "Product2", quantity: "3" }
​2: Object { id: "3", name: "Product3", quantity: "4" }
​3: Object { id: "4", name: "Product4", quantity: "2" }
​4: Object { id: "5", name: "Product5", quantity: "6" }
​5: Object { id: "6", name: "Product6", quantity: "11" }

值得我的php代码如下:

数据.php

<?php
require_once 'database.php';
$stmt = $conn->prepare('select * from product');
$stmt->execute();
$results = $stmt->fetchAll(PDO::FETCH_OBJ);
echo json_encode($results); 
?>

数据库.php

<?php
$conn = new PDO('mysql:host=192.168.99.100;dbname=demo','root', 'root');
?>

备注:this版本相似但略有不同

Answer 1

你可以实际使用

google.charts.load

代替

$(文档).ready

它应该是 z 而不是 s

可视化

不是

可视化

像这样尝试......

google.charts.load('current', {
  packages: ['corechart']
}).then(function () {
  $.ajax({
    url:"data.php",
    dataType : "JSON",
    success : function(result) {
      drawChart(result);
    }
  });
});

function drawChart(result) {
    var data = new google.visualization.Datatable();
    data.addColumn('string','Name');
    data.addColumn('number','Quantity');
    $.each(result, function(i, obj) {
        data.addRow([ obj.name, parseInt(obj.quantity) ]);
    });

    var piechart_options = {
        title : 'Pie Chart: How Much Products Sold By Last Night',
        width : 400,
        height : 300
    }
    var piechart = new google.visualization.PieChart(document
            .getElementById('piechart_div'));
    piechart.draw(data, piechart_options)

    var barchart_options = {
        title : 'Bar Chart: How Much Products Sold By Last Night',
        width : 400,
        height : 300,
        legend : 'none'
    }
    var barchart = new google.visualization.BarChart(document
            .getElementById('barchart_div'));
    barchart.draw(data, barchart_options)
}