我有一个如下所示的数组:
0: {ID: null,
name: "test",
city: "Austin",
UserColors: [{color: "blue"},{hobby:"beach"} ... ]}
}...
我正在尝试 ng-repeat 初始数组，但是一旦我尝试遍历列表，我什么也看不到，这是 html/angular
<tr ng-repeat="c in vm.people">
<td>{{c.name}}</td>
<td>{{c.city}}</td>
<td ng-repeat="uc in c.UserColors">
<td>{{uc.color}}</td>
</td>
</tr>
我不确定哪里出了问题，非常感谢您的帮助，在此先感谢您。
最佳答案
我将使用自定义过滤器处理该字段:
<td ng-repeat-start="(key, value) in c.UserColors | reduce">
<b>{{key}}</b>
</td>
<td ng-repeat-end>
{{value}}
</td>
过滤器:
app.filter("reduce",function() {
return function(items) {
var x = items.map(o => Object.entries(o));
var x2 = x.reduce(((a,x) => (a.concat(x))), []);
var x3 = x2.reduce(((o,x) => (o[x[0]]=x[1],o)), {});
return x3;
}
})
The DEMO
angular.module("app",[])
.controller("ctrl",function(){
var vm = this;
vm.people = {
0: {ID: null,
name: "test",
city: "Austin",
UserColors: [{color: "blue"},{hobby:"beach"}]
},
1: {ID: null,
name: "best",
city: "Boston",
UserColors: [{colorx: "red"},{shirt:"black"}]
},
2: {ID: null,
name: "rest",
city: "Paris",
UserColors: [{colory: "yel"},{fruit:"peach"}]
},
}
})
.filter("reduce",function() {
return function(items) {
var x = items.map(o => Object.entries(o));
var x2 = x.reduce(((a,x) => (a.concat(x))), []);
var x3 = x2.reduce(((o,x) => (o[x[0]]=x[1],o)), {});
return x3;//items;
}
})<script src="//unpkg.com/angular/angular.js"></script>
<body ng-app="app" ng-controller="ctrl as vm">
<h3>Table</h3>
<table>
<tr ng-repeat="c in vm.people">
<td>{{c.name}}</td>
<td>{{c.city}}</td>
<td ng-repeat-start="(key, value) in c.UserColors | reduce">
<b>{{key}}</b>
</td>
<td ng-repeat-end>
{{value}}
</td>
</tr>
</table>
</body>关于javascript - Angularjs:如何 ng-repeat 具有也是数组的字段的对象数组？，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/50707766/