我正在使用 Sequelize 关系查询指定客户的客户订单。
index.js
var results2 = await customerService.getOrders(1);
console.log(results2);
service.js
exports.getOrders = function (id) {
return customerModel.findAll({
raw: true,
include: [{
model: orderModel,
where: { customer_idcustomer: id }
}],
}).then(r => r);
};
结果
[ { idcustomer: 1,
customername: 'hello world',
'orders.idorder': 1,
'orders.orderdesc': 'order description 1',
'orders.customer_idcustomer': 1 },
{ idcustomer: 1,
customername: 'hello world',
'orders.idorder': 2,
'orders.orderdesc': 'Test 456',
'orders.customer_idcustomer': 1 },
{ idcustomer: 1,
customername: 'hello world',
'orders.idorder': 3,
'orders.orderdesc': 'Test 123',
'orders.customer_idcustomer': 1 } ]
预期
[ { idcustomer: 1,
customername: 'hello world',
'orders: [{
'orders.idorder': 1,
'orders.orderdesc': 'order description 1',
'orders.customer_idcustomer': 1 },
},
{
'orders.idorder': 2,
'orders.orderdesc': 'order description 2',
'orders.customer_idcustomer': 1 },
},
{
'orders.idorder': 3,
'orders.orderdesc': 'order description 3',
'orders.customer_idcustomer': 1 },
}]
]
最佳答案
您所需要做的就是从查询中删除 raw: true,
因为它将返回普通/平面对象,并且这会将您的对象转换为现在的样子。
exports.getOrders = function (id) {
return customerModel.findAll({
// raw: true, // <------ Just remove this line
include: [{
model: orderModel,
where: { customer_idcustomer: id }
}],
}).then(r => r);
};
Note : You should put the where condition in upper level as per your logic
exports.getOrders = function (id) {
return customerModel.findAll({
where: { id: id } ,
// raw: true, // <------ Just remove this line
include: [{
model: orderModel
}]
}).then(r => r);
};
关于javascript - Sequelize关系查询返回重复数据,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/51118940/