我在一个 geojson 多边形文件中有属性,这些属性是工作日的不同组合,如下所示: 周一至周五或周二至周五或周二、周三、周五或周一、周四或周三至周五等。
我需要的是在 Leaflet 中显示文本字符串中没有值“Mon”(星期一)的多边形。 我怎样才能过滤掉这个?我正在使用此代码进行其他过滤...
var non_mon = new L.layerGroup();
$.getJSON("..data/polygons.geojson", function(json) {
var vectorGrid = L.vectorGrid.slicer(json, {
maxZoom: 20,
rendererFactory: L.svg.tile,
vectorTileLayerStyles: {
sliced: function(properties, zoom){
var dayint = properties.Days_1
if (dayint = "does not have Mån" ){
return{
weight: 0.5,
color: '#ffffff',
opacity: 1,
fill: true,
fillColor: '#ff0000',
stroke: true,
fillOpacity: 0.6
}
} else {
return {
weight: 0,
fill: false,
stroke: false
}
}
}},
interactive: true,
})
.on('click', function(e) {
var properties = e.layer.properties;
L.popup()
.setContent(
"<b>Weekdays</b>" + '\xa0\xa0' + properties.Days_1 + '</b>' +
"<br>Date from: " + '<i>' + properties.Date + '</i>' )
.setLatLng(e.latlng)
.openOn(map);
})
vectorGrid.addTo(non_mon)
})
这就是 GeoJSON 的样子
{ "type": "Feature", "properties": { "Days_1": "Mån-Fre" },
{ "type": "Feature", "properties": { "Days_1": "Tis-Fre" },
{ "type": "Feature", "properties": { "Days_1": "Ons-Fre" },
{ "type": "Feature", "properties": { "Days_1": "Tors,Fre" },
{ "type": "Feature", "properties": { "Days_1": "Mån,Ons,Fre" },
{ "type": "Feature", "properties": { "Days_1": "Tis,Ons-Fre" },
{ "type": "Feature", "properties": { "Days_1": "Ons,Tors" },
{ "type": "Feature", "properties": { "Days_1": "Mån" },
{ "type": "Feature", "properties": { "Days_1": "Tis" },
{ "type": "Feature", "properties": { "Days_1": "Ons" },
{ "type": "Feature", "properties": { "Days_1": "Tors" },
{ "type": "Feature", "properties": { "Days_1": "Fre" },
{ "type": "Feature", "properties": { "Days_1": "Tis-Tors" },
{ "type": "Feature", "properties": { "Days_1": "Mån-Tors" },
{ "type": "Feature", "properties": { "Days_1": "Ons,Fre" },
{ "type": "Feature", "properties": { "Days_1": null },
最佳答案
好的,所以您要筛选“Days_1”属性不包含字符串“Mån”的所有行。你可以这样做:
var geoJson = [...]; // Your GeoJSON
// After this function call 'filtered' contains the filtered list of GeoJSON features
var filtered = geoJson.filter(
function(element) {
// We are only interested in elements which do not contain 'Mån'
return element.indexOf("Mån") != -1;
}
);
在此示例中,我们使用数组原型(prototype)的“filter”方法部分。 filter 方法将为数组中的每个元素调用传递的函数。然后您可以返回 true 以保留该元素或返回 false 以过滤该元素。最终结果将作为一个新数组返回。
关于javascript - 过滤javascript中不存在的txt字符串的一部分,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/52623315/