所以我有一个字符串数组需要整理。
假设我有这个数组:
let array = ["8AD", "8AB", "8A6", "8BC", "86F", "835", "81D"];
现在,有两种排序需要实现:
- 字母字符优先于数字字符
- 数字字符优先于字母字符
现在,我需要对每个字符使用这两个中的任何一个进行排序。
因此,数字-数字-字母顺序会给我:
"81D","835","86F","8AB","8AD","8A6","8BC"
虽然数字-字母-数字顺序会给我:
"8A6","8AB","8AD","8BC","81D","835","86F"
我正在考虑将每个单个数字和所有字符分配给一个两位数的整数:
let alpha = {
A= 11, B= 12 , C= 13 , D= 14 , E= 15 , F= 16 , G= 17 , H= 18 , I= 19 , J= 20 , K= 21,
L= 22 , M= 23 , N= 24 , O= 25 , P= 26 , Q= 27 , R= 28 , S= 29 , T= 30 , U= 31 , V= 32,
W= 33 , X= 34 , Y= 35 , Z= 36 , 0=37, 1= 38 , 2= 39 , 3= 40 , 4= 41 , 5= 42 , 6= 43 , 7= 44,
8= 45 , 9= 46 };
let numeral = {
0=11, 1=12, 2=13, 3=14, 4=15, 5=16, 6=17, 7=18, 8=19, 9=20, A=21,
B=22, C=23, D=24, E=25, F=26, G=27, H=28, I=29, J=30, K=31, L=32,
M=33, N=34, O=35, P=36, Q=37, R=38, S=39, T=40, U=41, V=42, W=43,
X=44, Y=45, Z=46 }
然后将每个字符替换为所需的顺序。 有没有人有更简单或更有效的方法来实现需要做的事情?
最佳答案
这是一些通用/抽象的东西
// given a sequence and an array of "order" strings, create a comparable "key" string
let multiSortKey = (subject, orders) =>
[...subject].map(
(c, i) =>
String(orders[i].indexOf(c)).padStart(16, '0')
).join();
// generic comparison function
let cmp = (a, b) => (a > b) - (a < b);
// generic sort-by-map, aka Schwartzian, function
let sortBy = (xs, key) => xs
.map(x => [x, key(x)])
.sort((x, y) => cmp(x[1], y[1]))
.map(x => x[0]);
// applied to the task at hand:
data = ["8AD", "8AB", "8A6", "8BC", "86F", "835", "81D"]
N = '0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ'
A = 'ABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789'
console.log(sortBy(data, x => multiSortKey(x, [N, N, A])))
console.log(sortBy(data, x => multiSortKey(x, [N, A, N])))
关于javascript - 按字母或数字字符对字符串数组进行排序,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/52700037/