javascript - 如何修复 VUEX 中的状态变化？

Question

我在从另一个数组拼接元素然后更改状态时更改状态时遇到问题。明确一点，我不想改变状态，只想拼接数组 arrayWithFilters = []

中的一个元素

export const SHOW_RESULTS_WHEN_NOTHING = (state) => {
  let selectedFilters = {...state.selected.filters},
  arrayWithFilters = []; //Making splice from this array, but it also removes from state.selected.filters. 

  for (let filter in selectedFilters) {
    arrayWithFilters.push(selectedFilters[filter])
  }

  arrayWithFilters.forEach((filter) => {
    if (filter.values.includes('qcontrast')) {
      filter.values.splice('qcolor', 1);
      console.log(filter)
    }
  })
}

Answer 1

下一段代码解决了问题

export const SHOW_RESULTS_WHEN_NOTHING = (state) => {
let selectedFilters = {...state.selected.filters},
    arrayWithFilters = [];

let selectedFiltersCopy = JSON.parse(JSON.stringify(selectedFilters));

arrayWithFilters = Object.values(selectedFiltersCopy);

arrayWithFilters.forEach((filter) => {

    if (filter.values.includes('qcontrast')) {

        filter.values.splice('qcontrast', 1);

    }
})

console.log(arrayWithFilters)