java - org.hibernate.dialect.OracleDialect 不支持身份 key 生成

Question

我试图将一个示例项目导入到 Eclipse 中，但在运行应用程序时遇到了以下给定的错误。

Caused by: org.hibernate.MappingException: org.hibernate.dialect.OracleDialect does not support identity key generation
    at org.hibernate.dialect.Dialect.getIdentityColumnString(Dialect.java:743)
    at org.hibernate.dialect.Dialect.getIdentityColumnString(Dialect.java:733)
    at org.hibernate.mapping.Table.sqlCreateString(Table.java:426)
    at org.hibernate.cfg.Configuration.generateSchemaCreationScript(Configuration.java:1028)
    at org.hibernate.tool.hbm2ddl.SchemaExport.<init>(SchemaExport.java:125)
    at org.hibernate.internal.SessionFactoryImpl.<init>(SessionFactoryImpl.java:492)
    at org.hibernate.cfg.Configuration.buildSessionFactory(Configuration.java:1744)
    at org.hibernate.cfg.Configuration.buildSessionFactory(Configuration.java:1782)
    at org.springframework.orm.hibernate4.LocalSessionFactoryBuilder.buildSessionFactory(LocalSessionFactoryBuilder.java:247)
    at org.springframework.orm.hibernate4.LocalSessionFactoryBean.buildSessionFactory(LocalSessionFactoryBean.java:373)
    at org.springframework.orm.hibernate4.LocalSessionFactoryBean.afterPropertiesSet(LocalSessionFactoryBean.java:358)
    at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.invokeInitMethods(AbstractAutowireCapableBeanFactory.java:1541)
    at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.initializeBean(AbstractAutowireCapableBeanFactory.java:1479)
    ... 32 more

根据 this SO链接，我已经更改了

@GeneratedValue(strategy = GenerationType.IDENTITY)

到

@GeneratedValue(strategy = GenerationType.AUTO) 或 @GeneratedValue(strategy = GenerationType.TABLE)

但是没用。

代码如下:

用户.java:

@Entity
@Table(name = "users")
@ManagedBean
@ViewScoped
public class User {

    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    private int id;

    @Column(name = "username", nullable = false)
    private String username;

    @Column(name = "password", nullable = false)
    private String password;

    @Column(name = "role", nullable = false)
    private String role;

    public int getId() {
        return id;
    }

    public void setId(int id) {
        this.id = id;
    }

    public String getUsername() {
        return username;
    }

    public void setUsername(String username) {
        this.username = username;
    }

    public String getPassword() {
        return password;
    }

    public void setPassword(String password) {
        this.password = password;
    }

    public String getRole() {
        return role;
    }

    public void setRole(String role) {
        this.role = role;
    }

    }

来自 applicationContext.xml:

<!-- Session Factory Declaration -->
<bean id="SessionFactory"
    class="org.springframework.orm.hibernate4.LocalSessionFactoryBean">
    <property name="dataSource" ref="DataSource" />
    <property name="annotatedClasses">
        <list>
            <value>com.crud.model.User</value>
        </list>
    </property>
    <property name="hibernateProperties">
        <props>
            <prop key="hibernate.dialect">org.hibernate.dialect.OracleDialect</prop>
            <prop key="hibernate.show_sql">true</prop>
            <prop key="hibernate.hbm2ddl.auto">create</prop>

        </props>
    </property>
</bean>

Answer 1

您可以使用告诉 Hibernate 使用序列来生成您的 ID

@Id
@Column(name = "ID")
@GeneratedValue(strategy=GenerationType.SEQUENCE, generator = "id_Sequence")
@SequenceGenerator(name = "id_Sequence", sequenceName = "ID_SEQ")
private int id;

这个配置基本上告诉 Hibernate 使用一个名为 ID_SEQ 的数据库序列来为这个对象生成 ID。如果您想要其他唯一 ID，您可以在其他对象上指定其他序列，或者如果您想要整个系统的全局唯一 ID，您可以使用相同的序列。

唯一的缺点是不能执行批量插入(没有一些进一步的配置)因为Hibernate每次都需要从数据库中获取下一个序列值，如果你想使用你不能使用这个配置MySQL 数据库，因为它们不支持序列。

如果有任何不明白的地方请告诉我，我会进一步解释。