我有来自 Patrick Brockmann's CollapsibleTree Search 的以下代码它用 D3 树节点填充 Select2 列表。我想改变这个，所以只有最后一个节点/叶子在列表中，而不是父节点。我该怎么做？
//===============================================
function select2DataCollectName( d ) {
if ( d.children )
d.children.forEach( select2DataCollectName );
else if ( d._children )
d._children.forEach( select2DataCollectName );
select2Data.push( d.name );
}
//===============================================
function searchTree( d ) {
if ( d.children )
d.children.forEach( searchTree );
else if ( d._children )
d._children.forEach( searchTree );
var searchFieldValue = eval( searchField );
if ( searchFieldValue && searchFieldValue.match( searchText ) ) {
// Walk parent chain
var ancestors = [];
var parent = d;
while ( typeof ( parent ) !== "undefined" ) {
ancestors.push( parent );
//console.log(parent);
parent.class = "found";
parent = parent.parent;
}
//console.log(ancestors);
}
}
//===============================================
$( "#search" ).on( "select2-selecting", function ( e ) {
clearAll( root );
expandAll( root );
update( root );
searchField = "d.name";
searchText = e.object.text;
searchTree( root );
root.children.forEach( collapseAllNotFound );
update( root );
} )
最佳答案
最好的想法是重构所有功能...
function select2DataCollectName(d) {
if (d.children)
d.children.forEach(select2DataCollectName);
else if (d._children)
d._children.forEach(select2DataCollectName);
select2Data.push(d.name);
}
...避免不必要的递归。
但是，作为快速回答，您可以简单地检查对象中是否没有 children 属性:
if(!d.children) select2Data.push(d.name);
这是 fork 的 bl.ocks:http://bl.ocks.org/GerardoFurtado/75f9ac822aace4165caeca1708ee510d/2e24099a8f7d6157783f9d2099754d6abc085a93
关于javascript - 搜索列表，只需要叶子，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/57519520/