java - 将 InputStream 转换为 JSON

Question

我正在使用 json-rpc-1.0.jar。下面是我的代码。我需要将 InputStream 对象转换为 JSON，因为响应是 JSON。

我确实验证了从 Zappos API 获得的 json 响应。有效。

PrintWriter out = resp.getWriter();
String jsonString = null;
URL url = new URL("http://api.zappos.com/Search?term=boots&key=my_key");
InputStream inputStream = url.openConnection().getInputStream();
resp.setContentType("application/json");

JSONSerializer jsonSerializer = new JSONSerializer();
try {
   jsonString = jsonSerializer.toJSON(inputStream);
} catch (MarshallException e) {
 e.printStackTrace();
    }
out.print(jsonString);

我得到下面提到的异常:

com.metaparadigm.jsonrpc.MarshallException: can't marshall sun.net.www.protocol.http.HttpURLConnection$HttpInputStream
    at com.metaparadigm.jsonrpc.JSONSerializer.marshall(JSONSerializer.java:251)
    at com.metaparadigm.jsonrpc.JSONSerializer.toJSON(JSONSerializer.java:259)
    at Communicator.doGet(Communicator.java:33)
    at javax.servlet.http.HttpServlet.service(HttpServlet.java:740)
    at javax.servlet.http.HttpServlet.service(HttpServlet.java:853)
    at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:247)
    at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:193)
    at filters.ExampleFilter.doFilter(ExampleFilter.java:149)

Answer 1

利用 Jackson JSON 解析器。

引用 - Jackson Home

你唯一需要做的 -

ObjectMapper mapper = new ObjectMapper();
Map<String, Object> jsonMap = mapper.readValue(inputStream, Map.class);

现在 jsonMap 将包含 JSON。