我刚开始了解 Coffescript,发现需要从特定属性最小的数组中选择一个对象。我在下面列出了我的基本代码:
class Point
constructor: (@x, @y, @z) ->
addedTogether: ->
@x+@y+@z
class PointCollection
constructor: ->
@points = []
add: (point) ->
@points.push(point)
minimalPoint: ->
// need to return point with lowest addedTogether value
samplePoints = new PointCollection()
samplePoints.add(new Point(1,2,3))
samplePoints.add(new Point(2,3,4))
samplePoints.add(new Point(3,4,5))
samplePoints.add(new Point(4,5,6))
samplePoints.add(new Point(5,6,7))
samplePoints.add(new Point(1,1,1))
lowestValuePoint = samplePoints.minimalPoint()
我显然可以在普通的旧 javascript 中使用如下函数来做到这一点:
function findPointWithLowestScore(points) {
var lowestScoringPoint = points[0];
for (var i = 0; i < points.length; i++) {
lowestScoringPoint = (points[i].addedTogether() < lowestScoringPoint.addedTogether()) ? points[i] : lowestScoringPoint;
}
return lowestScoringPoint;
}
但是是否有更好、更简洁、符合 CoffeeScript 风格的方式来做到这一点?
最佳答案
尝试这样的事情:
class Point
constructor: (@x, @y, @z) ->
addedTogether: ->
@x+@y+@z
class PointCollection
constructor: ->
@points = []
add: (point) ->
@points.push(point)
minimalPoint: ->
tmp = @points.slice 0 # duplicate array
tmp.sort (a, b) -> a.addedTogether() - b.addedTogether() # Sort from lowest to highest
tmp[0] # Return the first element
samplePoints = new PointCollection()
samplePoints.add(new Point(1,2,3))
samplePoints.add(new Point(2,3,4))
samplePoints.add(new Point(3,4,5))
samplePoints.add(new Point(4,5,6))
samplePoints.add(new Point(5,6,7))
samplePoints.add(new Point(1,1,1))
lowestValuePoint = samplePoints.minimalPoint()
关于javascript - 如何从某个属性最小的数组中选择一个对象?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/9094807/