javascript - innerHTML 上的错误分配替换

Question

我以前从来没有用 Javascript 做过任何事情，在试图用 tampermonkey 制作一个 chrome 用户脚本之后我似乎无法完成这个 Action ......这个功能工作得很好，但是当我这样做时我一直收到错误的分配或没有错误，但操作不会通过...这可能看起来非常丑陋或糟糕，但关于如何根据文本是否为 25-1

感谢任何能提供帮助的人。

function W01() 
{       
if (/another 25 seconds before attempting to search again/i.test (document.body.innerHTML) )
{
    document.body.innerHTML() = document.body.innerHTML.replace('Sorry, but you can only perform one search every 25 seconds. Please wait another 25 seconds before attempting to search again.', 'Press F5 or Reload the page now');
}
else if (/another 24 seconds before attempting to search again/i.test (document.body.innerHTML) )
{
    document.body.innerHTML() = document.body.innerHTML.replace('Sorry, but you can only perform one search every 25 seconds. Please wait another 24 seconds before attempting to search again.', 'Press F5 or Reload the page now');
}
    else if (/another 23 seconds before attempting to search again/i.test (document.body.innerHTML) )
    {
        document.body.innerHTML() = document.body.innerHTML.replace('Sorry, but you can only perform one search every 25 seconds. Please wait another 23 seconds before attempting to search again.', 'Press F5 or Reload the page now');
    }
}

Answer 1

删除innerHTML()中的()。

应该是:

document.body.innerHTML = "some HTML";

请注意，它不是函数。这是一个属性。

例如这样做:

document.body.innerHTML = document.body.innerHTML.replace('Sorry, but you can only perform one search every 25 seconds. Please wait another 23 seconds before attempting to search again.', 'Press F5 or Reload the page now');