javascript - 从数组返回对象时排除属性？

Question

var users = [
    {name: tim, password: 123, connected: true}, 
    {name: jim, password: 345, connected: true}, 
    {name: kim, password: 678, connected: true, admin: true}, 
    {name: pim, password: 91011}
];

var connectedUsers = users.filter(function( connectedUser ) {
    if(!connectedUser.admin) {
        return connectedUser.connected;
        //not sure how to return the connected users object without the password attr
    }
});

以上返回所有连接的用户，这是为我的应用程序构建一个 api，只有管理员可以访问此路由并且密码已加密，但我想将它们从请求中排除。那么如何过滤排除密码属性的对象呢？

Answer 1

filter() 用于过滤条目；即，如果您为某个条目返回 true，则它会包含在结果中，否则会被丢弃。因此，您不能使用 filter() 来转换输入。相反，您应该将过滤后的结果映射到没有密码的对象:

var users = [
    {name: 'tim', password: '123', connected: true}, 
    {name: 'jim', password: '345', connected: true}, 
    {name: 'kim', password: '678', connected: true, admin: true}, 
    {name: 'pim', password: '91011'}
];
users.filter(function( connectedUser ) {
    return !connectedUser.admin && connectedUser.connected;
}).map(function(user) {
    // return {name: user.name, connected: user.connected}
    // __OR__
    // EDIT1: You can as the following to delete only one
    // field if the user object is very large. You can also
    // use JQuery's clone() method instead of stringify/parse.
    userCopy = JSON.parse(JSON.stringify(user))
    delete userCopy.password
    return userCopy
})

附言。我对您的过滤器功能做了一个小改动。