javascript - 在 JavaScript 中使用 If 语句

Question

我决定在 JavaScript 中添加以下 if 语句

  if (form.address == "Vancouver, BC") {
      user.set("address", "#complete address");
} else if (form.address == "Edmonton, AB") {
      user.set("address", "complete address");
} else if (form.address == "Vancouver + United States") {
      user.set("address", "#complete address And 1300 Boblett Street, US");
} else if (form.address == "Edmonton + United States") {
      user.set("address", "complete address");
} 

并且在控制台上收到以下错误:

TypeError: object is not a function

完整代码如下

 $scope.signUp = function(form) {
    var user = new Parse.User();
    user.set("password", form.password);
        user.set("username", form.username);
                user.set("fullName", form.fname);

      user.set("companyName", form.cname);
      if (form.address == "Vancouver, BC") {
      user.set("address", "#1001 - 610 Granville Street Vancouver, BC V6C 3J3");
} else if (form.address == "Edmonton, AB") {
      user.set("address", "10915 65th Ave NW Edmonton, AB T6H 1W1");
} else if (form.address == "Vancouver + United States") {
      user.set("address", "#1001 - 610 Granville Street Vancouver, BC V6C 3J3 And 1300 Boblett Street, Unit-B1569 Blaine, WA 98230");
} else if (form.address == "Edmonton + United States") {
      user.set("address", "10915 65th Ave NW Edmonton, AB T6H 1W1 And 1300 Boblett Street, Unit-B1569 Blaine, WA 98230");
} 

           user.set("phoneNumber", form.pnumber);
          user.set("mailingAddress", form.maddress);
          user.set("plan", form.plan);


    user.signUp(null, {
      success: function(user) {
  window.location = 'payment.php'
      },
      error: function(user, error) {
      var div = document.getElementById("signUpError");
    div.textContent = "Unable to sign up: " + error.message;
     scroll(0,0);
      }
    });    
  };

本质上有一个表单，其中有一个选项输入来选择一个地址，例如当某些人选择纽约时，它会存储到解析该位置的完整地址(用户只能看到纽约，但后端存储完整地址)。

Answer 1

当您看到这种类型错误时，您是在将某个未定义为函数的函数调用。 例如:

var user = {
set: {
        phone: '',
        address:''
    }
};
user.set("phoneNumber", "form.pnumber");