嗨，这看起来很简单，但它不起作用!我正在尝试获取两个 Epoch 数字并计算当天循环中的星期几。我需要这个，因为我不想计算周末的天数(即 0 或 6)。
<!DOCTYPE html>
<html>
<body>
<p>Click the button to display todays day of the week.</p>
<button onclick="myFunction()">Try it</button>
<p id="demo"></p>
<script>
function myFunction() {
var oneDay = 86400;
var days = 0;
var currDay = 0;
//var d = new Date();
// get the start time in Epoch
var dayTime = 1425531600 //from the user selection
var endTime = 1425960000
//while our dayTime is less than the end time,
//loop through the days and count them.
while (dayTime < endTime) {
// advance one day
dayTime = dayTime + oneDay;
document.write("out:"+dayTime+"<br>")
//turn the new time in Epoch into a date
var d = new Date(dayTime);
document.write("out:"+d.getDay()+"<br>")
}
}
</script>
</body>
</html>
输出看起来像这样:
out:1425618000
out:6
out:1425704400
out:6
out:1425790800
out:6
out:1425877200
out:6
out:1425963600
out:6
为什么每个纪元我总是得到“6”？我的 Epoch 值有问题吗？请注意，它是 5 天，所以每天的长度为 86400。
我将代码复制到此页面中进行测试: http://www.w3schools.com/jsref/tryit.asp?filename=tryjsref_getday
最佳答案
在 new Date(x) 中，x 需要采用 unixEpoch 格式 (毫秒) - 或 other formats .要解决您的问题，只需将所有值乘以 1000:
window.onload = function() {
var oneDay = 86400000;
var days = 0;
var currDay = 0;
//var d = new Date();
// get the start time in Epoch
var dayTime = 1425531600000 //from the user selection
var endTime = 1425960000000
//while our dayTime is less than the end time,
//loop through the days and count them.
while (dayTime < endTime) {
// advance one day
dayTime = dayTime + oneDay;
document.body.insertAdjacentHTML('beforeend',"out:" + dayTime + "<br>")
//turn the new time in Epoch into a date
var d = new Date(dayTime);
document.body.insertAdjacentHTML('beforeend',"out:" + d.getDay() + "<br>")
}
}关于javascript - Javascript 中 getDay 的问题，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/28953243/