javascript - 将行添加到表并发送到服务器，通过 jquery 将表发布到 php

Question

我正在尝试制作一个表格，我可以在其中通过单击按钮添加新行，然后将表格发送到服务器，以便它记住页面刷新时的信息。下面是一个按钮，它成功地将一行添加到具有当前时间的表中。但是，当我通过“发送到服务器”按钮将表格发送到服务器时，它不会回显更新后的表格，只会回显原始表格。弄清楚这个问题真是令人欣慰。

HTML:

<input type = "button" id = "send" value = "Send to Server" />
<input type = "button" id = "add" value = "Add Row" />
<table class="table table-striped">
        <tr>
            <td><h2>In</h2></td>
            <td><h2>Out</h2></td>
            <td><h2>Total</h2></td>
        </tr>
        <tr>
            <td>InData</td>
            <td>OutData</td>
            <td>TotalData</td>
        </tr>
</table>

JS:

<script language="javascript" type="text/javascript" src="jquery-1.8.2.js"></script>
<script language="javascript" type="text/javascript">

$("#add").click(function(){

    var dt = new Date();
    var time = dt.getHours() + ":" + dt.getMinutes() + ":" + dt.getSeconds(); //set variable to current time
    $('table > tbody:last').append('<tr><td>'+time+'</td><td></td><td></td></tr>'); //add row to table with current time

});

$(function(){
    var dataArr = [];
    $("table").each(function(){
        dataArr.push($(this).html());
    });
    $('#send').click(function(){
        $.ajax({
          type : "POST",
          url : 'timesheet.php',
          data : "content="+dataArr,
          success: function(data) {
              alert(data);// alert the data from the server
          },
          error : function() {
          }
         });
    });
});
</script

PHP(时间表.php):

<?php 
    echo $_REQUEST['content'];
?>

Answer 1

when I send the table to the server via the "Send to Server" button it does not echo back the updated table, only the original.

解决方案

使用 .on() 代替 .click()

<script language="javascript" type="text/javascript" src="jquery-1.8.2.js"></script>
<script language="javascript" type="text/javascript">

$(document).on('click', '#add', function(){

    var dt = new Date();
    var time = dt.getHours() + ":" + dt.getMinutes() + ":" + dt.getSeconds(); //set variable to current time
    $('table > tbody:last').append('<tr><td>'+time+'</td><td></td><td></td></tr>'); //add row to table with current time

});

$(document).on('click', '#send', function(){
    var dataArr = [];
    $("table").each(function(){
        dataArr.push($(this).html());
    });
    $('#send').click(function(){
        $.ajax({
          type : "POST",
          url : 'timesheet.php',
          data : "content="+dataArr,
          success: function(data) {
              alert(data);// alert the data from the server
          },
          error : function() {
          }
         });
    });
});
</script>

已编辑:

您正在使用的 click() 绑定(bind)称为“直接”绑定(bind)，它只会将处理程序附加到已经存在 的元素。它不会绑定(bind)到将来创建的元素。为此，您必须使用 on() 创建一个“委托(delegate)”绑定(bind)。

来自documentation of .on() :

Delegated events have the advantage that they can process events from descendant elements that are added to the document at a later time.