我正在尝试更新 Alfresco 中的文件...我编写了以下代码:
var csrf_header = Alfresco.util.CSRFPolicy.getHeader();
var csrf_token = Alfresco.util.CSRFPolicy.getToken();
function getResponse(pdfbase64) {
var fd = new FormData();
if (Alfresco.util.CSRFPolicy && Alfresco.util.CSRFPolicy.isFilterEnabled())
{
fd.append(csrf_header, csrf_token);
}
fd.append("username", "admin");
fd.append("updatenoderef", nodeRef);
fd.append("filedata", pdfbase64);
fd.append("majorversion", "true");
fd.append("overwrite", "true");
alert(fileUpdateURL);
$.ajax({
url: fileUpdateURL,
type: "POST",
data: fd,
processData: false, // tell jQuery not to process the data
contentType: false // tell jQuery not to set contentType
});
}
变量 pdfbase64
是要放在文件中的内容(我对文件所做的更改以更新 base64 中的文件),但也许这不是正确的格式?, nodeRef
是文件的引用,例如:"workspace://SpacesStore/4fb1b7e7-2502-4011-8870-17e8d626b93b"
和 fileUpdateURL
是URL
到 POST
:http://localhost:8080/share/proxy/alfresco/api/upload
我得到了错误:
POST http://localhost:8080/share/proxy/alfresco/api/upload 500 Internal Server Error
javax.servlet.ServletException: Possible CSRF attack noted when comparing token in session and request parameter. Request: POST /share/proxy/alfresco/api/upload at org.alfresco.web.site.servlet.CSRFFilter$AssertTokenAction.run(CSRFFilter.java:845) at org.alfresco.web.site.servlet.CSRFFilter.doFilter(CSRFFilter.java:312) at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:241 ) at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:208) at org.alfresco.web.site.servlet.SSOAuthenticationFilter.doFilter(SSOAuthenticationFilter.java:447)
at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:241 ) at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:208) at org.alfresco.web.site.servlet.MTAuthenticationFilter.doFilter(MTAuthenticationFilter.java:74) at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:241 ) at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:208) at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:220) at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:122) at org.apache.catalina.authenticator.AuthenticatorBase.invoke(AuthenticatorBase.java:504) at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:170) at org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:103) at org.apache.catalina.valves.AccessLogValve.invoke(AccessLogValve.java:950) at org.apache.catalina.core.StandardEngineValve.invoke(StandardEngineValve.java:116) at org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:421) at org.apache.coyote.http11.AbstractHttp11Processor.process(AbstractHttp11Processor.java:1074) at org.apache.coyote.AbstractProtocol$AbstractConnectionHandler.process(AbstractProtocol.java:611) at org.apache.tomcat.util.net.AprEndpoint$SocketProcessor.doRun(AprEndpoint.java:2466) at org.apache.tomcat.util.net.AprEndpoint$SocketProcessor.run(AprEndpoint.java:2455) at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1142) at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:617) at org.apache.tomcat.util.threads.TaskThread$WrappingRunnable.run(TaskThread.java:61) at java.lang.Thread.run(Thread.java:745)
编辑: 如果我使用
代替
我得到错误:
{
"status" :
{
"code" : 400,
"name" : "Bad Request",
"description" : "Request sent by the client was syntactically incorrect."
},
"message" : "Required parameters are missing",
"exception" : "",
"callstack" :
[
],
"server" : "Community v5.0.0 (d r99759-b2) schema 8,022",
"time" : "Jan 24, 2016 1:14:41 PM"
}
谁能帮帮我?
编辑2:
我尝试使用 http://localhost:8080/share/proxy/alfresco/api/upload 发出请求有了这个:
function getResponse(pdfbase64) {
var csrf_header = Alfresco.util.CSRFPolicy.getHeader();
var csrf_token = Alfresco.util.CSRFPolicy.getToken();
var fd = new FormData();
if (Alfresco.util.CSRFPolicy && Alfresco.util.CSRFPolicy.isFilterEnabled())
{
fd.append(csrf_header, csrf_token);
fileUpdateURL += "?" + Alfresco.util.CSRFPolicy.getParameter() + "=" + encodeURIComponent(Alfresco.util.CSRFPolicy.getToken());
}
fd.append("username", "admin");
fd.append("updatenoderef", nodeRef);
fd.append("filedata", pdfbase64);
fd.append("majorversion", "true");
fd.append("overwrite", "true");
alert(fileUpdateURL);
$.ajax({
url: fileUpdateURL,
type: "POST",
data: fd,
processData: false, // tell jQuery not to process the data
contentType: false // tell jQuery not to set contentType
});
}
但是我得到了错误:
{
"status" :
{
"code" : 400,
"name" : "Bad Request",
"description" : "Request sent by the client was syntactically incorrect."
},
"message" : "Required parameters are missing",
"exception" : "",
"callstack" :
[
],
"server" : "Community v5.0.0 (d r99759-b2) schema 8,022",
"time" : "Jan 24, 2016 1:14:41 PM"
}
最佳答案
尝试在您的函数中移动这些行:
var csrf_header = Alfresco.util.CSRFPolicy.getHeader();
var csrf_token = Alfresco.util.CSRFPolicy.getToken();
如果这不能解决您的问题,并且问题证明不是 csrf_*
变量的变量范围问题,那么您应该尝试 here 中的提示 (2)
更新: 正如我在聊天中解释的那样,您应该替换:
fd.append("filedata", pdfbase64);
与:
fd.append("filedata", new Blob([pdfbase64], {type: 'application/pdf'}););
关于javascript - Alfresco 更新文件 - 错误发布,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/34975107/