首先，除了我的函数中的问题，我不确定我的代码中是否遗漏了任何东西，但我离题了。我是 jquery 的新手，所以我在设置注册页面时遇到了困难。在表单中，我试图检查有效条目以及使用 php 检查后端中的查询。我设置了 2 个文件，一个是 html 文件，另一个是 php 文件。使用 ajax 函数应该调用 php 文件，但我似乎无法让它工作，我想知道是否应该将所有代码放在同一个文件中。此外，我不确定这些功能是否能正常工作，因为它没有返回任何状态。我将在下面发布两个文件的代码。任何提示或技巧将不胜感激。
没有CSS的HTML文件
<!DOCTYPE html>
<html >
<head>
<meta charset="UTF-8">
<title>Register</title>
<link rel="stylesheet" href="assets/css/reset.css">
<link rel="stylesheet" href="assets/css/style.css">
</head>
<body>
<script src="assets/js/jquery.min.js"> </script>
<script src="assets/js/main.js"> </script>
<div class="pen-title">
<h1>Registration Form</h1></div>
<script>
function emptyElement(x){
_(x).innerHTML = "";
}
function signup(){
var u = _("username").value;
var e = _("email").value;
var p1 = _("pass").value;
var p2 = _("pass2").value;
var status = _("status");
if(u == "" || e == "" || p1 == "" || p2 == ""){
status.innerHTML = "Fill out all of the form data";
} else if(p1 != p2){
status.innerHTML = "Your password fields do not match";
} else
{
_("submit").style.display = "none";
status.innerHTML = 'please wait ...';
var ajax = ajaxObj("POST", "registration.php");
ajax.onreadystatechange = function() {
if(ajaxReturn(ajax) == true) {
if(ajax.responseText != "signup_success"){
status.innerHTML = ajax.responseText;
_("submit").style.display = "block";
} else {
window.scrollTo(0,0);
_("signupform").innerHTML = "OK "+u+", check your email inbox and junk mail box at <u>"+e+"</u> in a moment to complete the sign up process by activating your account. You will not be able to do anything on the site until you successfully activate your account.";
}
}
}
ajax.send("u="+u+"&e="+e+"&p="+p1);
}
}
</script>
<!-- Form Module-->
<div class="module form-module">
<div class="form">
</div>
<div class="form">
<h2>Create an account</h2>
<form method="post" name="signupform" id="signupform" onsubmit="return false;">
<input type="text" id="username" onfocus="emptyElement('status')" placeholder="Username" maxlength="50"/>
<input type="password" id="pass" onfocus="emptyElement('status')" placeholder="Password" maxlength="10"/>
<input type="password" id="pass2" onfocus="emptyElement('status')" placeholder="Confirm Password" maxlength="10"/>
<input type="email" id="email" onfocus="emptyElement('status')" placeholder="Email Address" maxlength="50"/>
<!-- <input type="tel" name="telephone" placeholder="Phone Number" maxlength="10"/> -->
<button type="submit" onclick="signup()" name="submit">Register</button>
</form>
</div>
</div>
</body>
</html>
PHP文件
<?php
// Connects to your Database
$host="myhost"; // Host name
$username="myuser"; // Mysql username
$password="mypass"; // Mysql password
$db_name="mydbname"; // Database name
$con = mysqli_connect("$host", "$username", "$password", "$db_name") or die(mysql_error());
// Ajax calls this REGISTRATION code to execute
if(isset($_POST["u"])){
// GATHER THE POSTED DATA INTO LOCAL VARIABLES
$u = preg_replace('#[^a-z0-9]#i', '', $_POST['u']);
$e = mysqli_real_escape_string($con, $_POST['e']);
$p = $_POST['p'];
// GET USER IP ADDRESS
$ip = preg_replace('#[^0-9.]#', '', getenv('REMOTE_ADDR'));
// DUPLICATE DATA CHECKS FOR USERNAME AND EMAIL
$sql = "SELECT id FROM users WHERE username='$u' LIMIT 1";
$query = mysqli_query($con, $sql);
$u_check = mysqli_num_rows($query);
// -------------------------------------------
$sql = "SELECT id FROM users WHERE email='$e' LIMIT 1";
$query = mysqli_query($con, $sql);
$e_check = mysqli_num_rows($query);
// FORM DATA ERROR HANDLING
if($u == "" || $e == "" || $p == ""){
echo "The form submission is missing values.";
exit();
} else if ($u_check > 0){
echo "The username you entered is alreay taken";
exit();
} else if ($e_check > 0){
echo "That email address is already in use in the system";
exit();
} else if (strlen($u) < 3 || strlen($u) > 16) {
echo "Username must be between 3 and 16 characters";
exit();
} else if (is_numeric($u[0])) {
echo 'Username cannot begin with a number';
exit();
} else {
// END FORM DATA ERROR HANDLING
// Begin Insertion of data into the database
// Hash the password and apply your own mysterious unique salt
//$cryptpass = crypt($p);
//include_once ("php_includes/randStrGen.php");
//$p_hash = randStrGen(20)."$cryptpass".randStrGen(20);
// Add user info into the database table for the main site table
$sql = "INSERT INTO users (username, email, password, ip, signup, lastlogin, notescheck)
VALUES('$u','$e','$p' ,'$ip',now(),now(),now())";
$query = mysqli_query($con, $sql);
$uid = mysqli_insert_id($con);
// Establish their row in the useroptions table
$sql = "INSERT INTO useroptions (id, username, background) VALUES ('$uid','$u','original')";
$query = mysqli_query($db_conx, $sql);
// Create directory(folder) to hold each user's files(pics, MP3s, etc.)
//if (!file_exists("user/$u")) {
// mkdir("user/$u", 0755);
//}
}
}
?>
最佳答案
您的 javascript 代码有很多错误。就像您使用 _ 而不是 $ 并且您的元素 ID 是错误的。它们不包括#。所以我用你的逻辑组织了你的代码。但这不是真正的问题，也不是真正的学习方法。 HTML
<!DOCTYPE html>
<html >
<head>
<meta charset="UTF-8">
<title>Register</title>
<link rel="stylesheet" href="assets/css/reset.css">
<link rel="stylesheet" href="assets/css/style.css">
</head>
<body>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.1.0/jquery.min.js"></script>
<!--script src="assets/js/main.js"> </script-->
<div class="pen-title">
<h1>Registration Form</h1></div>
<script>
function emptyElement(x){
$('#' + x).text("");
}
function signup(){
var un = $("#username").val();
var em = $("#email").val();
var p1 = $("#pass").val();
var p2 = $("#pass2").val();
if(un == "" || em == "" || p1 == "" || p2 == "")
{
$('#status').text("Fill out all of the form data");
}
else if(p1 != p2)
{
$('#status').text("Your password fields do not match");
}
else
{
$.ajax({
type: "POST",
url: "registration.php",
dataType: "json",
data : { u: un, p:p1, e:em },
cache: !1,
beforeSend: function(){
$("#submit").hide();
$('#status').text('please wait ...');
},
complete: function(){
$("#submit").show();
},
success: function(answer){
if(answer.result == "successful")
{
$("#status").html(answer.text);
}
else
{
$("#status").html(answer.result);
}
},
error: function(answer){
$("#status").text(answer);
}
});
}
/*
var ajax = ajaxObj("POST", "registration.php");
ajax.onreadystatechange = function() {
if(ajaxReturn(ajax) == true) {
if(ajax.responseText != "signup_success"){
status.innerHTML = ajax.responseText;
$("submit").style.display = "block";
} else {
window.scrollTo(0,0);
$("signupform").innerHTML = "OK "+u+", check your email inbox and junk mail box at <u>"+e+"</u> in a moment to complete the sign up process by activating your account. You will not be able to do anything on the site until you successfully activate your account.";
}
}
}
ajax.send("u="+u+"&e="+e+"&p="+p1);
*/
}
</script>
<!-- Form Module-->
<div class="module form-module">
<div class="form">
</div>
<div class="form">
<h2>Create an account</h2>
<form method="post" name="signupform" id="signupform" onsubmit="return false;">
<input type="text" id="username" onfocus="emptyElement('status')" placeholder="Username" maxlength="50"/>
<input type="password" id="pass" onfocus="emptyElement('status')" placeholder="Password" maxlength="10"/>
<input type="password" id="pass2" onfocus="emptyElement('status')" placeholder="Confirm Password" maxlength="10"/>
<input type="email" id="email" onfocus="emptyElement('status')" placeholder="Email Address" maxlength="50"/>
<!-- <input type="tel" name="telephone" placeholder="Phone Number" maxlength="10"/> -->
<button type="submit" onclick="signup()" name="submit">Register</button>
<div id="status"></div>
</form>
</div>
</div>
</body>
</html>
注册.php
<?php
$answer = new stdClass;
if(isset($_POST))
{
$answer->result = "successful";
$answer->text = "";
foreach($_POST as $key => $value)
{
$answer->text .= $key . ": " . $value . "<br />";
}
}
else
{
$answer->result = "Error";
$answer->text = "Error Message";
}
echo json_encode($answer);
?>
这个 registration.php 是一个例子。你可以用你的逻辑重写。
您应该使用 $answer 对象进行响应。
$answer->result 是响应状态
$answer->text 是响应
我希望它能帮助你。
关于javascript - Ajax/Jquery 问题将数据推送到后端，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/39795967/