我有一个 web API返回以下 JSON:
[{"MovieId":2,"Title":"End Game","Year":"2013","Actors":"Cuba Gooding Jr., Angie Harmon, James Woods, Patrick Fabian","Plot":"A secret Service agent and a news reporter investigate the conspiracy behind the assassination of the President","Director":"Andy Cheng","Cover":"Endgame-movie-cover.jpg"},{"MovieId":3,"Title":"Saving Private Ryan","Year":"1998","Actors":"Tom Hanks, Tom Sizemore, Edward Burns, Barry Pepper","Plot":"Following the Normandy Landings, a group of U.S. soldiers go behind enemy lines to retrieve a paratrooper whose brothers have been killed in action","Director":"Steven Spielberg","Cover":"Saving-Private-Ryan-Cover.jpg"}]
我想在我的 AJAX 调用之后将 JSON 从响应传递给 jqGrid 以填充表中的数据，如下所示:
function fetchMovies(){
$.ajax({
url: 'http://orionadmin.azurewebsites.net/api/movies',
type: 'GET',
datatype: 'JSON',
contentType: 'application/json',
success: function (data) {
grid_data1 = JSON.stringify(data);
alert(grid_data);
},
error: function (x, h, r) {
alert('Something went wrong')
}
});
}
AJAX 调用的结果如下所示:
"[{"MovieId":2,"Title":"End Game","Year":"2013","Actors":"Cuba Gooding Jr., Angie Harmon, James Woods, Patrick Fabian","Plot":"A secret Service agent and a news reporter investigate the conspiracy behind the assassination of the President","Director":"Andy Cheng","Cover":"Endgame-movie-cover.jpg"},{"MovieId":3,"Title":"Saving Private Ryan","Year":"1998","Actors":"Tom Hanks, Tom Sizemore, Edward Burns, Barry Pepper","Plot":"Following the Normandy Landings, a group of U.S. soldiers go behind enemy lines to retrieve a paratrooper whose brothers have been killed in action","Director":"Steven Spielberg","Cover":"Saving-Private-Ryan-Cover.jpg"}]"
这是 jqGrid 采用的格式，用于填充表中的数据:
<script type="text/javascript">
var grid_data =
[
{id:"1",name:"Desktop Computer",note:"note",stock:"Yes",ship:"FedEx", sdate:"2007-12-03"},
{id:"2",name:"Laptop",note:"Long text ",stock:"Yes",ship:"InTime",sdate:"2007-12-03"},
{id:"3",name:"LCD Monitor",note:"note3",stock:"Yes",ship:"TNT",sdate:"2007-12-03"},
{id:"4",name:"Speakers",note:"note",stock:"No",ship:"ARAMEX",sdate:"2007-12-03"},
{id:"5",name:"Laser Printer",note:"note2",stock:"Yes",ship:"FedEx",sdate:"2007-12-03"},
{id:"6",name:"Play Station",note:"note3",stock:"No", ship:"FedEx",sdate:"2007-12-03"},
{id:"7",name:"Mobile Telephone",note:"note",stock:"Yes",ship:"ARAMEX",sdate:"2007-12-03"},
{id:"8",name:"Server",note:"note2",stock:"Yes",ship:"TNT",sdate:"2007-12-03"},
{id:"9",name:"Matrix Printer",note:"note3",stock:"No", ship:"FedEx",sdate:"2007-12-03"},
{id:"10",name:"Desktop Computer",note:"note",stock:"Yes",ship:"FedEx", sdate:"2007-12-03"},
{id:"11",name:"Laptop",note:"Long text ",stock:"Yes",ship:"InTime",sdate:"2007-12-03"},
{id:"12",name:"LCD Monitor",note:"note3",stock:"Yes",ship:"TNT",sdate:"2007-12-03"},
{id:"13",name:"Speakers",note:"note",stock:"No",ship:"ARAMEX",sdate:"2007-12-03"},
{id:"14",name:"Laser Printer",note:"note2",stock:"Yes",ship:"FedEx",sdate:"2007-12-03"},
{id:"15",name:"Play Station",note:"note3",stock:"No", ship:"FedEx",sdate:"2007-12-03"},
{id:"16",name:"Mobile Telephone",note:"note",stock:"Yes",ship:"ARAMEX",sdate:"2007-12-03"},
{id:"17",name:"Server",note:"note2",stock:"Yes",ship:"TNT",sdate:"2007-12-03"},
{id:"18",name:"Matrix Printer",note:"note3",stock:"No", ship:"FedEx",sdate:"2007-12-03"},
{id:"19",name:"Matrix Printer",note:"note3",stock:"No", ship:"FedEx",sdate:"2007-12-03"},
{id:"20",name:"Desktop Computer",note:"note",stock:"Yes",ship:"FedEx", sdate:"2007-12-03"},
{id:"21",name:"Laptop",note:"Long text ",stock:"Yes",ship:"InTime",sdate:"2007-12-03"},
{id:"22",name:"LCD Monitor",note:"note3",stock:"Yes",ship:"TNT",sdate:"2007-12-03"},
{id:"23",name:"Speakers",note:"note",stock:"No",ship:"ARAMEX",sdate:"2007-12-03"}
];
在 AJAX 调用之后，如何在没有 "" 的情况下保持原始 JSON 格式，以便我可以在我的 jqGrid 中显示我的数据？
最佳答案
也许是这样的？
'[{"MovieId":2,"Title":"End Game","Year"...'.replace(new RegExp('"', 'g'), '')
关于javascript - 在 AJAX 调用后，如何从 Web API 响应中维护相同的 JSON 格式？，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/41274429/