Java 以较弱的访问权限实现接口(interface)方法时出错

Question

当我编译这段代码时:

interface Rideable {
    String getGait();
}

public class Camel implements Rideable {
    int x = 2;

    public static void main(String[] args) {
        new Camel().go(8);
    }

    void go(int speed) {
        System.out.println((++speed * x++) 
        + this.getGait());
    }

    String getGait() {
        return " mph, lope";
    }
}

我收到以下错误:

Camel.java:13: error: getGait() in Camel cannot implement getGait() in Rideable
String getGait() {
       ^
  attempting to assign weaker access privileges; was public
1 error

接口(interface)中声明的getGait方法如何被认为是public的？

Answer 1

在接口(interface)内声明的方法是隐式public。并且接口(interface)中声明的所有变量都是隐式public static final(常量)。

public String getGait() {
  return " mph, lope";
}