javascript - 将 pickBy 和 mapValues 从 lodash 转换为函数

Question

我正在尝试将这个使用 pickBy 和 mapValues 的函数从 lodash 转换为不使用 lodash 的函数。

import mapValues from 'lodash/mapValues';
import pickBy from 'lodash/pickBy';

    function clinicsWithInvitations(upcomingClinics) {
      const upClinics = upcomingClinics.clinics;
      const upInvitations = upcomingClinics.invitations;

      const getInvitations = id => pickBy(upInvitations, inv => inv.clinicId === id);
      const mergeInvitations = (clinic, clinicId) => ({
        ...clinic,
        invitations: getInvitations(clinicId),
      });

      return mapValues(upClinics, mergeInvitations);
    }

我试过了，没用

function clinicsWithInvitations(upcomingClinics) {
  const upClinics = upcomingClinics.clinics;
  const upInvitations = upcomingClinics.invitations;

  const getInvitations = clinicId =>
    Object.keys(upInvitations).reduce((acc, invId) => {
      const inv = upInvitations[invId];
      return inv.clinicId === clinicId ? { ...acc, [inv.clinicId]: inv } : acc;
    }, {});

  const mergeInvitations = (acc, clinicId) => ({
    ...acc,
    [clinicId]: {
      ...upClinics[clinicId],
      invitations: getInvitations(clinicId),
    },
  });
  return Object.keys(upClinics).reduce(mergeInvitations, {});
}

我想做的是将两个对象合并为一个对象，我试图将诊所与邀请相关联，同时考虑到 clinicId，所以我有这个:

const upcomingClinics = {
  "clinics": {
    "a0CW000000271LuMAI": {
      "id": "a0CW000000271LuMAI",
      "contact": {
        "name": null,
        "phone": null,
        "email": null
      },
      "shifts": {
        "teamLeads": 1,
        "healthTechs": 1
      }
    },
    "a0CW00000026gikMAA": {
      "id": "a0CW00000026gikMAA",
      "contact": {
        "name": null,
        "phone": null,
        "email": null
      },
      "shifts": {
        "teamLeads": 1,
        "healthTechs": 4
      }
    }
  },
  "invitations": {
    "56392": {
      "id": "56392",
      "clinicId": "a0CW00000026gikMAA"
    },
    "56393": {
      "id": "56393",
      "clinicId": "a0CW00000026gikMAA"
    },
    "56402": {
      "id": "56402",
      "clinicId": "a0CW00000026gikMAA"
    },
    "56427": {
      "id": "56427",
      "clinicId": "a0CW000000271LuMAI"
    },
    "56428": {
      "id": "56428",
      "clinicId": "a0CW000000271LuMAI"
    }
  }
}

这是期望的输出，但不会引起任何突变。

const upcomingClinics = {
  "clinics": {
    "a0CW000000271LuMAI": {
      "id": "a0CW000000271LuMAI",
      "contact": {
        "name": null,
        "phone": null,
        "email": null
      },
      "shifts": {
        "teamLeads": 1,
        "healthTechs": 1
      }
      "invitations": {
        "56427": {
          "id": "56427",
          "clinicId": "a0CW000000271LuMAI"
        },
        "56428": {
          "id": "56428",
          "clinicId": "a0CW000000271LuMAI"
        }
      }
    },
    "a0CW00000026gikMAA": {
      "id": "a0CW00000026gikMAA",
      "contact": {
        "name": null,
        "phone": null,
        "email": null
      },
      "shifts": {
        "teamLeads": 1,
        "healthTechs": 4
      }
      "invitations": {
        "56392": {
          "id": "56392",
          "clinicId": "a0CW00000026gikMAA"
        },
        "56393": {
          "id": "56393",
          "clinicId": "a0CW00000026gikMAA"
        },
        "56402": {
          "id": "56402",
          "clinicId": "a0CW00000026gikMAA"
        },
      }
    }
  },
}

Answer 1

您当前的尝试看起来非常接近，但我认为您有一个小错字。这:

const getInvitations = clinicId =>
  Object.keys(upInvitations).reduce((acc, invId) => {
    const inv = upInvitations[invId];
    return inv.clinicId === clinicId ? { ...acc, [inv.clinicId]: inv } : acc;
  }, {});

...正在使用 [inv.clinicId] 作为键，当 invitations 属性为您想要的 invId 时由邀请 ID 键入:

const getInvitations = clinicId =>
  Object.keys(upInvitations).reduce((acc, invId) => {
    const inv = upInvitations[invId];
    return inv.clinicId === clinicId ? { ...acc, [invId]: inv } : acc;
  }, {});