java - java中如何获取执行目录路径

Question

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Answer 1

正如 Jarrod Roberson 在 his answer here 中所说的那样:

One way would be to use the system property System.getProperty("user.dir"); this will give you "The current working directory when the properties were initialized". This is probably what you want. to find out where the java command was issued, in your case in the directory with the files to process, even though the actual .jar file might reside somewhere else on the machine. Having the directory of the actual .jar file isn't that useful in most cases.

The following will print out the current directory from where the command was invoked regardless where the .class or .jar file the .class file is in.

public class Test
{
    public static void main(final String[] args)
    {
        final String dir = System.getProperty("user.dir");
        System.out.println("current dir = " + dir);
    }
}  

if you are in /User/me/ and your .jar file containing the above code is in /opt/some/nested/dir/ the command java -jar /opt/some/nested/dir/test.jar Test will output current dir = /User/me.

You should also as a bonus look at using a good object oriented command line argument parser. I highly recommend JSAP, the Java Simple Argument Parser. This would let you use System.getProperty("user.dir") and alternatively pass in something else to over-ride the behavior. A much more maintainable solution. This would make passing in the directory to process very easy to do, and be able to fall back on user.dir if nothing was passed in.

示例:获取执行路径

import java.util.*;
import java.lang.*;

public class GetExecutionPath
{
  public static void main(String args[]) {
    try{
      String executionPath = System.getProperty("user.dir");
      System.out.print("Executing at =>"+executionPath.replace("\\", "/"));
    }catch (Exception e){
      System.out.println("Exception caught ="+e.getMessage());
    }
  }
}

上面的输出是这样的

C:\javaexamples>javac GetExecutionPath.jav

C:\javaexamples>java GetExecutionPath
Executing at =>C:/javaexamples