我需要显示 3 个集合中的数据,然后按日期对它们进行排序。问题是我无法找到正确的数据结构来进行设置。
我必须像这样返回一个对象:
data : {
total, // the total number of objects in collections
data // the data from all the three collections
}
这是我要设置的代码:
const fillAray = (callb) => {
let total = 0;
let totalData={}
for(let i=0;i<3;i++){
switch(i){
case 0:
historyPart='1st table'
break;
case 1:
historyPart='2nd table'
break;
case 2:
historyPart='3rd table'
break;
}
const collection_ref = admin.firestore().collection(`*****-${historyPart}`);
const user_transactions_ref = collection_ref.doc(uid).collection('transactions');
user_transactions_ref.orderBy('time', 'desc').get().then(
(snapshot) => {
if (!snapshot.empty) {
snapshot.forEach((doc) => {
++total;
});
}
user_transactions_ref.orderBy('time', 'desc').offset(from).limit(size).get().then(
(snapshot) => {
const out = [];
if (!snapshot.empty) {
snapshot.forEach((doc) => {
out.push(doc.data())
});
}
//merging data
Object.assign(totalData,out)
},
(error) => { callback(error, null); }
);
},
(error) => { callback(error, null); }
);
}
sendDataToFront(totalData,total)
// Here I'm supposed to have totalData and total with all datas
}
不知何故对象没有正确合并......有什么想法吗?
最佳答案
目前还不清楚您要在这里实现什么,但是合并多个查询的通用方法看起来像这样:
const refA = admin.firestore().collection('foo/A/widgets');
const refB = admin.firestore().collection('foo/B/widgets');
// fetch data in parallel
Promise.all([ refA.get(), refB.get() ])
// merge the results
.then(promiseResults => {
const mergedData = [];
promiseResults.forEach( snapshot => {
snapshot.forEach( doc => mergedData.push(doc.data()) );
});
return mergedData;
})
// sort the results
.then(mergedData => mergedData.sort((a, b) => a.timestamp - b.timestamp))
// use the results
.then(sortedData => {
// do something with data here
console.log(sortedData);
})
// log any errors
.catch(e => console.error(e));
关于javascript - 如何使用 Firebase 合并多个集合?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/54482517/